Câu hỏi của Phạm Bảo Nhi

Question

1/3 + 1/6 + 1/ 10 + .... + 1/300

''  Giúp mik với . Cảm ơn .  ''

Yen Nhi · Accepted Answer

$\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+...+\dfrac{1}{300}$

$=2.\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{24.25}\right)$

$=2.\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{24}-\dfrac{1}{25}\right)$

$=2.\left(\dfrac{1}{2}-\dfrac{1}{25}\right)$

$=\dfrac{23}{25}$Câu trả lời: $\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+...+\dfrac{1}{300}$

$=2.\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{24.25}\right)$

$=2.\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{24}-\dfrac{1}{25}\right)$

$=2.\left(\dfrac{1}{2}-\dfrac{1}{25}\right)$

$=\dfrac{23}{25}$

Phạm Bảo Nhi · Answer

cảm ơn bn yến nhi nhaCâu trả lời: cảm ơn bn yến nhi nha