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`129*172-73*129+129`
$=129*(172-73+1) \\=129*100\\=12900$
129.72 - 73.129 = 129
=129. (172-73+1 )
=129.100
=12900
=>12900
1)...=135+65+360+40+24=200+400+24=624
2)...=(8.125).(4.25)=1000.100=100000
4)...= (467+433)+(238+762)+3465=990+1000+3465=5455
5)...=129.(172-73+1)=129.100=12900
6)...=205-(1200-(16-6)3):40=205-(1200-1000):40=205-200:40=205-5=200
\(A=\frac{12}{40}+\frac{12}{88}+\frac{12}{154}+\frac{12}{238}+\frac{12}{340}\)
\(A=\frac{12}{5\times8}+\frac{12}{8\times11}+\frac{12}{11\times14}+\frac{12}{14\times17}+\frac{12}{17.20}\)
\(A=4\times\left(\frac{3}{5\times8}+\frac{3}{8\times11}+\frac{3}{11\times14}+\frac{3}{14\times17}+\frac{3}{17\times20}\right)\)
\(A=4\times\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}+\frac{1}{17}-\frac{1}{20}\right)\)
\(A=4\times\left(\frac{1}{5}-\frac{1}{20}\right)\)
\(A=4\times\frac{3}{20}=\frac{12}{20}=\frac{3}{5}\)
các bạn vào link này để thi đua cùng mình nha:
https://iostudy.net/ref/132310
ai vào mình tích đúng 5 lần
a: \(=\dfrac{6}{4}\left(\dfrac{4}{4\cdot8}+\dfrac{4}{8\cdot12}+...+\dfrac{4}{76\cdot80}\right)\)
\(=\dfrac{3}{2}\left(\dfrac{1}{4}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{12}+...+\dfrac{1}{76}-\dfrac{1}{80}\right)\)
\(=\dfrac{3}{2}\cdot\dfrac{19}{80}=\dfrac{57}{160}\)
b: \(=2\left(\dfrac{6}{6\cdot12}+\dfrac{6}{12\cdot18}+...+\dfrac{6}{54\cdot60}\right)\)
\(=2\left(\dfrac{1}{6}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{18}+...+\dfrac{1}{54}-\dfrac{1}{60}\right)\)
\(=2\cdot\dfrac{9}{60}=\dfrac{18}{60}=\dfrac{3}{10}\)
A=129-128-127-126-125-124-123-122-121-120
A.12=1210-129-128-127-126-125-124-123-122-120
A.11=(1210-129-128-127-126-125-124-123-122-120)-(129-128-127-126-125-124-123-122-120)
A.11=1210-12
A=1210.11-11.12
= 129 . ( 172 - 73 + 12 )
= 123 . 111
= 1679319