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\(B=1+2+4+...+4096\)
\(B=1+2+2^2+2^3+...+2^{12}\)
\(2B=2+2^2+...+2^{13}\)
\(2B-B=\left(2+2^2+...+2^{13}\right)-\left(1+2+...+2^{12}\right)\)
\(B=2^{13}-1\)
B=1+2+4+8+...+4098
B=\(1+2+2^2+2^3+....+2^{12}\)
2B=\(2+2^2+2^3+2^4+.....+2^{13}\)
2B-B=\(\left(2+2^2+2^3+2^4+...+2^{13}\right)-\left(1+2+2^2+2^3...+2^{12}\right)\)
B=\(2^{13}-1\)
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\(\frac{-7}{12}+\frac{11}{8}-\frac{5}{9}\)
\(=\frac{-42}{72}+\frac{99}{72}+\frac{-40}{72}\)
\(=\frac{17}{72}\)
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Đặt A=1/2+1/4+1/8+...+1/256
2A=2/4+2/8+2/16+...+2/512
2A—A=(2/4+2/8+2/16+...+2/512—1/2+1/4+1/8+...+1/256)
A=2/512—1/2
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a; 100 - 94 + 90 - 84 + 80 - 74 + 70 - 64 + 60 - 54
= (100 - 94) + (90 - 84) + (80 - 74) + (70 - 64) + (60 - 54)
= 6 + 6 + 6 + 6 + 6
A = 6 x 5
A = 30
b; 5.125.20.16
= (5.20). (125.8).2
= 100.1000.2
= 200000
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A = 1 . 3 + 3 . 5 + 5 . 7 + ... + 49 . 51
A=1*51
A=
B = 2 . 4 + 4 . 6 + 6 . 8 + ... + 98 . 100
B=2*100
B=200
C = 1 . 4 + 4 . 7 + 7 . 10 + ... + 301 . 304
C=1*304
C=304
D = 1 + 1 . 1! + 2 . 2! + 3 . 3! + ... + 100 . 100!
D=1*100!
D=100!
E = 22 + 42 + ... + ( 2n )2
E=\(2^2\cdot2n^2\)
E=\(2n^4\)
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\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}<\frac{1}{2}+\frac{1}{2}+\frac{1}{4}+\frac{1}{4}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=2.\frac{1}{2}+2.\frac{1}{4}+3.\frac{1}{6}=2\)