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a: \(=\dfrac{1.8\cdot4.5}{0.25}\cdot\dfrac{1.4}{4.2}+4.33=\dfrac{32.4}{3}+4.33=10.8+4.33=15.13\)
b: \(=1003.55-3.55-999=1000-999=1\)
c: \(=3.78\left(200-68-100+68\right)=100\cdot3.78=378\)
d: \(=0.1\cdot\dfrac{\left(4.8+1.5\right)\cdot\left[\left(4.8-1.5\right):0.3+1\right]}{2}=3.78\)
Câu 3:
a) \(\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}\)
\(\dfrac{-16}{20}=\dfrac{-16:4}{20:4}=\dfrac{-4}{5}\)
b) \(\dfrac{21}{105}=\dfrac{21:21}{105:21}=\dfrac{1}{5}\)
\(\dfrac{35}{150}=\dfrac{35:5}{150:5}=\dfrac{7}{30}\)
Câu 4:
a) \(\dfrac{3}{10}+\dfrac{5}{10}=\dfrac{3+5}{10}=\dfrac{8}{10}=\dfrac{4}{5}\)
b) Ta có: \(\left(-27\right)\cdot36+64\cdot\left(-27\right)+23\cdot\left(-100\right)\)
\(=\left(-27\right)\cdot\left(64+36\right)+23\cdot\left(-100\right)\)
\(=-27\cdot100-23\cdot100\)
\(=100\left(-27-23\right)\)
\(=-50\cdot100=-5000\)
c) \(\dfrac{5}{8}+\dfrac{3}{12}=\dfrac{15}{24}+\dfrac{6}{24}=\dfrac{21}{24}=\dfrac{7}{8}\)
d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)
\(=\left(-\dfrac{2}{17}+\dfrac{-15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)
\(=-1+1+\dfrac{5}{6}\)
\(=\dfrac{5}{6}\)
a, \(\left|-46\right|+\left|12\right|+\left|100\right|=46+12+100=158\)
b, \(27\cdot\left(-2\right)^3\cdot\left(-7\right)\cdot\left(49\right)-456=27\cdot\left(-8\right)\cdot\left(-7\right)\cdot49-456=76033\)
# k dùm
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