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a, \(120\cdot15+12\cdot470+12\cdot38\cdot10\)
\(=12\cdot10\cdot15+12\cdot47\cdot10+12\cdot38\cdot10\)
\(=120\left(15+47+38\right)=120\cdot100=12000\)
f,\(\left(2+4+6+...+100\right)\cdot\left(36\cdot333-111\cdot108\right)\)
\(=\left(2+4+6+...+100\right)\cdot\left(36\cdot111\cdot3-111\cdot108\right)\)
\(=\left(2+4+6+...+100\right)\cdot111\cdot\left(36\cdot3-108\right)\)
\(=\left(2+4+6+...+100\right)\cdot111\cdot\left(108-108\right)\)
\(=\left(2+4+6+...+100\right)\cdot111\cdot0=0\)
a)
120.15+12.470+12.38.10
=120.15+120.47+120.38=120(15+47+38)=120.100=12000
b)
13.58.4+32.26.2+52.10
=52.58+52.26+52.10=52.(58+26+10)=52.100=5200
c)
3,2.990+32=32.99+32=32.(99+1)=32.100=3200
d)
45.(13+78)+9.(87+22).5
=45.91+45.109=45.(91+109)=45.200=9000
e)
(24+72+36+60):12=12.(2+6+3+5):12=16
f)(2+4+6+...+100)(36.333−108.111)
=(2+4+6+...+100)(36.3.111−36.3.111)=(2+4+6+...+100).0=0
1.(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)
=(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)
=(5.3^11+4.3^11.3):[3^9.(5^2-2^3)]
=(5.3^11+12.3^11):[3^9.17]
=3^11.(5+12):(3^9.17)
=(3^11.17):(3^9.17)
=17.(3^11:3^9)
=17.3^2
=17.9
=153
2.(12+22+32+...+992+1002).(36.333-108.111)
=2.(12+22+32+...+992+1002).(36.333-36.3.111)
=2.(12+22+32+...+992+1002).(36.333-36.333)
=2.(12+22+32+...+992+1002).0
=0
(1+2+3+...+1000).(108.111-36.333 )
=(1+2+3+...+1000).(108.111-36.3.111 )
=(1+2+3+...+1000).(108.111-108.111)
=(1+2+3+...+1000).0
= 0
a) = 13 x 24 + 24 x 76 + 11 x 24 d)= (1-2-3+4)+(5-6-7+8)+...+(97-98-99+100)
= 24 x ( 13 + 76 + 11 ) = 0 + 0 +...+ 0
= 24 x 100 =0
= 2400
CÓ VIỆC BẬN NÊN MÌNH CHỈ LÀM ĐC ĐẾN ĐÓ THÔI !
d) 1-2-3+4+5-6-7+...+97-98-99+100
=(1-2-3+4)+(5-6-7+8)+(9-10-11+12)+......+(97-98-99+100)
=0+0+0+0+.....+0
=0
Vay bang 0
1+2+3-4-5-6+...+97+98+99-100-101-102
=(1+2+3-4-5-6)+...+(97+98+99-100-101-102) có 17 cặp số
=(-9)+(-9)....+(-9) 17 cặp số
=(-9).17=-153
(12+22+32+...+102).(1+3+5...+97+99).(36.333-108.111) [ Đặt (12+22+32+...+102).(1+3+5...+97+99) = A]
= A. (36.3.111-108.111)
= A.(108.111-108.111)
= A.0
= 0
Vậy tích trên bằng 0
(12+22+32+...+102).(1+3+5...+97+99).(36.333-108.111)
= ( 12 + 22 + 32 + ... + 102 ) . ( 1 + 3 +5 + ... + 97 + 99 ) . ( 36 . 3 . 111 - 36 . 3 . 111 )
= ( 12 + 22 + 32 + ... + 102 ) . ( 1 + 3 +5 + ... + 97 + 99 ) . 0
= 0