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\(M=1-\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}\right)\)
\(=1-\left(\dfrac{3}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}\right)\)
\(=1-\left(\dfrac{7}{8}+\dfrac{1}{16}+\dfrac{1}{32}\right)\)
\(=1-\left(\dfrac{15}{16}+\dfrac{1}{32}\right)\)
\(=1-\dfrac{31}{32}=\dfrac{1}{32}\)
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)
\(=\frac{16}{32}+\frac{8}{32}+\frac{4}{32}+\frac{2}{32}+\frac{1}{32}\)
\(=\frac{31}{32}\)
Đặt A=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
A=1/21+1/22+1/23+1/24+1/25+1/26+1/27+1/28
1/2A=1/22+1/23+1/24+1/25+1/26+1/27+1/28+1/29
A-1/2A=(1/2+1/22+1/23+1/24+1/25+1/26+1/27+1/28)-(1/22+1/23+1/24+1/25+1/26+1/27+1/28+1/29)
1/2A=1/2-1/29
A=2(1/2-1/29)
A=1-1/28
A=28-1
b: A=1/3+1/9+...+1/3^10
=>3A=1+1/3+...+1/3^9
=>A*2=1-1/3^10=(3^10-1)/3^10
=>A=(3^10-1)/(2*3^10)
c: C=3/2+3/8+3/32+3/128+3/512
=>4C=6+3/2+...+3/128
=>3C=6-3/512
=>C=1023/512
d: A=1/2+...+1/256
=>2A=1+1/2+...+1/128
=>A=1-1/256=255/256
S=1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+...+1/(1+2+3+4+...+10)
S=1/(2*3/2)+1/(3*4/2)+1/(4*5/2)+...+1/(10*11/2)
S=2(1/(2*3)+1/(3*4)+1/(4*5)+1/(5*6)+...+1/(10*11)
S=2(1/2-1/3+1/3-1/4+1/4-1/5+...+1/10-1/11)
S=2(1/2-1/11)
S=2*9/22
S=9/11
nho k cho minh voi nha