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sorry tui làm sai câu này!!!
2/3 +4/37 +5/111 +260 /1443
=962/1443+156/1443+65/1443+260/1443
= 962+156+65+260/1443=1
tìm x
1)1/2 - ( x+3/14) = 1/6
=> x+3/14=1/2-1/6
=> x= 1/3 - 3/14
=> x= 5/42
2)( x- 1/3 ) -5/2 = 1/7
=> x-1/3= 1/7+5/2
=> x= 37/14+1/3
=> x= 125/42
3)5/8 + ( x- 1/4 ) = 4/3
=>x-1/4=4/3-5/8
=>x= 17/24 +1/4
=> x= 23/24
4) 4/3 - ( 1/4 -x ) =1
=>1/4-x=4/3-1
=>x=1/4-1/3
=> x= -1/12
Chúc bạn Hk tốt!!!
2/3 +4/37 +5/111 +260 /1443\(=\frac{635}{629}\)
Tìm x
1. \(x=\frac{5}{42}\)
2. \(x=\frac{125}{42}\)
3. \(x=\frac{23}{24}\)
4. \(x=-\frac{1}{12}\)
Chúc bạn Hk tốt!!!
OK
1. 1/2-(x-1/4)=1/3
=> x-1/4=1/2-1/3
=> x-1/4= 1/6
=> x= 1/6+1/4=5/12
2. 3/2*(x-1/2-1)=5/4
=> x-1/2-1=5/4:3/2
=> x-1/2= 5/6+1
=> x = 11/6+1/2
=> x= 7/3
3. 11/2-9/2*(x-3/4)=1
=> 9/2*(x-3/4)= 11/2-1
=> x-3/4 = 9/2:9/2
=> x= 1+3/4
=> x= 7/4
Chúc bạn Hk tốt!!!!!
1. x=\(\frac{5}{12}\)
2. x=\(\frac{7}{3}\)
3. x= \(\frac{7}{4}\)
Chúc bạn Hk tốt!!!
2+3/4=11/4 ; 2-3/5=7/5
5/7:6=5/42 ; 5+2/7=37/7
Bài 2: a) x-1/6=1/2+1/3
x-1/6=5/6
x=5/6+1/6
x=1
b) x+1/8=1/2-1/3
x+1/8=1/6
x=1/6-1/8
x=1/24
c) x:1/2=2/3.3/4
x:1/2=1/2
x=1/2.1/2
x =1/4
\(5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}x4\frac{1}{2}-2\frac{1}{2}\right):\frac{7}{4}\)
=\(\frac{59}{10}:\frac{3}{2}-\left(\frac{7}{3}x\frac{9}{2}-\frac{5}{2}\right):\frac{7}{4}\)
=\(\frac{118}{30}-\left(\frac{63}{6}-\frac{5}{2}\right)x\frac{4}{7}\)
=\(\frac{118}{30}-\left(\frac{63}{6}-\frac{15}{6}\right)x\frac{4}{7}\)
=\(\frac{118}{30}-8x\frac{4}{7}\)
=\(\frac{118}{30}-\frac{32}{7}\)
sau bn tự tính nha
bạn ghi đề rõ hơn được không
~~~~~~~~~~~~~
^_^
là (4 1phần 5 - 2 2phần 5 ) x 8 5 phần 6
bạn hiểu côn khác thì giúp mình
x-\(\frac{1}{4}\)=\(\frac{5}{3}\) x:\(\frac{2}{3}\)=\(\frac{1}{2}\)
x =\(\frac{5}{3}\)+\(\frac{1}{4}\) x =\(\frac{1}{2}\)x\(\frac{2}{3}\)
x =\(\frac{20}{12}\)+\(\frac{3}{12}\)=\(\frac{23}{12}\) x =\(\frac{2}{6}\)=\(\frac{1}{2}\)
Hok tốt!
@Kaito Kid
\(a)\) \(S=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+...+\frac{1}{2187}\)
\(S=1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^7}\)
\(3S=3+1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^6}\)
\(3S-S=\left(3+1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^6}\right)-\left(1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^7}\right)\)
\(2S=3+\frac{1}{3^7}\)
\(2S=\frac{3^8+1}{3^7}\)
\(S=\frac{3^8+1}{3^7}.\frac{1}{2}\)
\(S=\frac{3^8+1}{2.3^7}\)
Vậy \(S=\frac{3^8+1}{2.3^7}\)
Chúc bạn học tốt ~
các bạn giải ra từng bước giúp mình, mình đang cần gấp
\(\frac{2}{5}:\frac{1}{2}\)
\(=\frac{2.2}{5.1}\)
\(=\frac{4}{5}\)
\(\frac{4}{5}.\frac{1}{2}\)
\(=\frac{4.1}{5.2}\)
\(=\frac{4}{10}=\frac{2}{5}\)
1/2+1/3+2/5=37/30
2/3+3/4-1/5=73/60
4/5 * 1/2 = 2/5
2/5:1/2=4/5
đúng 100%