Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{2.4}{6.18}=\frac{1.2}{3.9}=\frac{2}{27}\)
\(\frac{3.5.7}{6.9.14}=\frac{1.5.7}{2.9.2}=\frac{35}{36}\)
\(\frac{4.7-4.5}{64}=\frac{4\left(7-5\right)}{64}=\frac{8}{64}=\frac{1}{8}\)
a)\(\frac{2.4}{6.18}\)=\(\frac{2.2.2}{2.3.2.3.3}\)=\(\frac{2.1.1}{1.3.1.3.3}\)=\(\frac{2}{27}\)
b)\(\frac{3.5.7}{6.9.14}\)=\(\frac{3.5.7}{2.3.3.3.2.7}\)=\(\frac{1.5.1}{2.1.3.3.2.1}\)=\(\frac{5}{36}\)
c)\(\frac{4.7-4.5}{64}\)=\(\frac{4.\left(7-5\right)}{64}\)=\(\frac{4.2}{64}\)=\(\frac{8}{64}\)=\(\frac{1}{8}\)
\(\frac{28}{36}=\frac{28:4}{36:4}=\frac{7}{9}\)
\(\frac{-63}{90}=\frac{-63:9}{90:9}=\frac{-7}{10}\)
\(\frac{40}{-120}=\frac{40:40}{-120:40}=\frac{1}{-3}\)
Bài 2:
\(\frac{2.4}{6.18}=\frac{2.2.2}{2.3.2.3.3}=\frac{2}{3.3.3}=\frac{2}{27}\)
\(\frac{3.5.7}{6.9.14}=\frac{3.5.7}{2.3.3.3.2.7}=\frac{5}{3.3.2.2}=\frac{5}{36}\)
\(\frac{4.7.\left(-4\right).5}{64}=\frac{4.7.\left(-4\right).5}{4.4.4}=\frac{7.\left(-5\right)}{4}=\frac{-35}{4}\)
1) Các phân số tối giản là: \(\frac{1}{5};\frac{5}{7};\frac{-2}{9}\)
2) a) \(\frac{28}{36}=\frac{28:4}{36:4}=\frac{7}{9}\)
b) \(\frac{-63}{90}=\frac{-63:9}{90:9}=\frac{-7}{10}\)
c) \(\frac{40}{-120}=\frac{40:40}{-120:40}=\frac{-1}{3}\)
3) a) \(\frac{2.4}{6.18}=\frac{2.2.2}{2.3.3.2.3}=\frac{2}{27}\)
b) \(\frac{3.5.7}{6.9.14}=\frac{3.5.7}{2.3.9.2.7}=\frac{5}{36}\)
c) \(\frac{4.7-4.5}{64}=\frac{4.\left(7-5\right)}{64}=\frac{4.2}{64}=\frac{8}{64}=\frac{1}{8}\)
4) Muốn rút gọn một phân số chưa tối giản, ta tìm ƯCLN của cả hai số ở tử và mẫu, rồi cùng đem cả tử và mẫu chia cho số chung vừa tìm được.
Đặt \(A=\dfrac{1}{1.2}+\dfrac{2}{2.4}+\dfrac{3}{4.7}+\dfrac{4}{7.11}+\dfrac{5}{11.16}+\dfrac{6}{16.22}\)
\(1A=1-\left(\dfrac{1}{2}+\dfrac{1}{2}\right)+\left(\dfrac{1}{4}+\dfrac{1}{4}\right)+\left(\dfrac{1}{7}+\dfrac{1}{7}\right)+\left(\dfrac{1}{11}+\dfrac{1}{11}\right)+\left(\dfrac{1}{16}+\dfrac{1}{16}\right)-\dfrac{1}{22}\)\(1A=1-\dfrac{1}{22}\)
\(1A=\dfrac{22}{22}-\dfrac{1}{22}\)
\(1A=\dfrac{21}{22}\)
\(\dfrac{21}{22}\) không thể rút gọn
\(A=\dfrac{1}{1\cdot2}+\dfrac{2}{2\cdot4}+\dfrac{3}{4\cdot7}+\dfrac{4}{7\cdot11}+\dfrac{5}{11\cdot16}+\dfrac{6}{16\cdot22}\\ =\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{22}\\ =1-\dfrac{1}{22}\\ =\dfrac{21}{22}\)
Vậy \(A=\dfrac{21}{22}\)
a: \(\dfrac{4\cdot5+4\cdot11}{8\cdot7+4\cdot3}=\dfrac{20+44}{56+12}=\dfrac{64}{68}=\dfrac{16}{17}=\dfrac{11088}{11781}\)
\(\dfrac{-15\cdot8+10\cdot7}{5\cdot6+20\cdot3}=\dfrac{-120+70}{30+60}=\dfrac{-50}{90}=\dfrac{-5}{9}=\dfrac{-6545}{11781}\)
\(\dfrac{2^4\cdot5^2\cdot7}{2^3\cdot5\cdot7^2\cdot11}=\dfrac{2\cdot5}{7\cdot11}=\dfrac{10}{77}=\dfrac{1530}{11781}\)
\(=\dfrac{6\cdot18}{12\cdot48}=\dfrac{6}{12}\cdot\dfrac{18}{48}=\dfrac{1}{2}\cdot\dfrac{3}{8}=\dfrac{3}{16}\)
a: \(=\dfrac{1}{1\cdot2}-\dfrac{1}{2\cdot3}+\dfrac{1}{2\cdot3}-\dfrac{1}{3\cdot4}+...+\dfrac{1}{18\cdot19}-\dfrac{1}{19\cdot20}\)
=1/2-1/380
=179/380
b: \(=\dfrac{1}{1\cdot3}-\dfrac{1}{3\cdot5}+\dfrac{1}{3\cdot5}-\dfrac{1}{5\cdot7}+...+\dfrac{1}{21\cdot23}-\dfrac{1}{23\cdot25}\)
\(=\dfrac{1}{3}-\dfrac{1}{575}=\dfrac{572}{1725}\)
c: \(=1+\dfrac{1}{2}-\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}-\dfrac{1}{20}-\dfrac{1}{21}\)
=1-1/21
=20/21
d: \(=\left(1-\dfrac{1}{9}\right)\left(1-\dfrac{1}{16}\right)\cdot...\cdot\left(1-\dfrac{1}{121}\right)\)
\(=\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot...\cdot\dfrac{10}{11}\cdot\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot...\cdot\dfrac{12}{11}\)
\(=\dfrac{2}{11}\cdot\dfrac{12}{2}=\dfrac{12}{11}\)
a, \(\dfrac{2.4}{6.18}\)=\(\dfrac{2}{27}\)
b,\(\dfrac{3.5.7}{6.9.14}\)=\(\dfrac{105}{756}\)=\(\dfrac{35}{232}\)
c,\(\dfrac{4.7-4.5}{64}\)=\(\dfrac{28-20}{64}\)=\(\dfrac{8}{64}\)=\(\dfrac{1}{8}\)
nhớ like nhé
\(\dfrac{2.4}{6.18}=\dfrac{8}{108}=\dfrac{2}{27}\)
\(\dfrac{3.5.7}{6.9.14}=\dfrac{105}{756}=\dfrac{35}{252}\)
\(\dfrac{4.7-4.5}{64}=\dfrac{4.\left(7-5\right)}{64}=\dfrac{4.2}{64}=\dfrac{8}{64}=\dfrac{1}{8}\)
Chúc bạn học tốt