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3. Tìm x
a, x : 912 =234 + 817
x : 912 = 1051
x = 1051 x 912
x = 958512
b, ( x : 26 -119 ) : 216 = 312
( x : 26 -119 ) = 312 x 216
( x : 26 -119 ) = 67392
x : 26 = 67392 + 119
x : 26 = 67511
x = 67511 x 26
x = 1755286
a) (x-32).45=0
( x - 32 ) = 0 : 45
( x -32 ) = 0
x = 0 + 32
x = 32
b) 25.(52-x)=25
( 52 - x ) = 25 : 25
( 52 - x ) = 1
=> x = 52 - 1 = 51
c) 231+(312-x)=531
( 312 - x ) = 531 - 231
( 312 - x ) = 300
x = 312 - 300
x = 12
d) ( 7x-15):3=2
( 7x - 15 ) = 2x 3
( 7x - 15 ) = 6
7x = 6 + 15
7x = 21
=> x = 21 :7
x = 3
a) \(\dfrac{7}{9}\times\dfrac{13}{25}\times\dfrac{9}{7}=\left(\dfrac{7}{9}\times\dfrac{9}{7}\right)\times\dfrac{13}{25}=1\times\dfrac{13}{25}=\dfrac{13}{25}\)
b) \(\dfrac{5}{9}\times\dfrac{21}{25}+\dfrac{21}{25}\times\dfrac{4}{9}\)
\(=\dfrac{21}{25}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\)
\(=\dfrac{21}{25}\times1=\dfrac{21}{25}\)
c) \(\dfrac{19}{5}\times\dfrac{11}{16}-\dfrac{9}{5}\times\dfrac{11}{16}\)
\(=\dfrac{11}{16}\times\left(\dfrac{19}{5}-\dfrac{9}{5}\right)\)
\(=\dfrac{11}{16}\times2=\dfrac{22}{16}=\dfrac{11}{8}\)
`234 xx 1257 - 234 xx 257`
`= 234 xx (1257 -257)`
`= 234 xx 1000`
`= 234000`
`312 xx 415 + 312 xx 574 + 312`
`=312 xx 415 + 312 xx 574 + 312xx1`
`=312 xx(415 + 574+1)`
`= 312 xx 1000`
`= 312000`
234×1257−234×257234×1257-234×257
=234×(1257−257)=234×(1257-257)
=234×1000=234×1000
=234000=234000
312×415+312×574+312312×415+312×574+312
=312×415+312×574+312×1=312×415+312×574+312×1
=312×(415+574+1)=312×(415+574+1)
=312×1000=312×1000
=312000
4 x 25 + 16x25 + 25
= 100 + 4x(4x25) + 25
= 125 + 4x100
= 125 + 400 = 525
\(25\times4+16\times25+25\)
\(=25\times\left(4+16+1\right)\)
\(=25\times21\)
\(=25\times\left(10+10+1\right)\)
\(=25\times10+25\times10+25\)
\(=250+250+25\)
\(=525\)
a. 312 x 425 + 312 x 574 + 312 = 312 × (425 + 574 + 1)
= 312 × 1000
= 312000
2174 x 312 + 688 x 2174 - 16 x 25
= 678288 + 1495712 - 400
= 2174000 - 400
= 2173600
=2174x (312+688)-16x 25
=2174x 1000-400
=2174000-400
=2173600