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LH
1
13 tháng 7 2019
\(1\frac{1}{7}.1\frac{1}{24}.\left(-5,1\right)\)
\(=\frac{8}{7}\cdot\frac{25}{24}\cdot\left(-5,1\right)\)
\(=\frac{25}{21}.\left(-5,1\right)\)
\(=-\frac{85}{14}\)
NP
3
TN
17 tháng 10 2016
\(\frac{41}{33}\)\(\frac{1043}{333}\)\(\frac{461}{90}\)\(\frac{73}{3300}\)
A
17 tháng 10 2016
\(1,\left(24\right)\)\(=\)\(1\frac{24}{99}\)\(=\)\(\frac{123}{99}\)
\(3,\left(132\right)\)\(=\)\(3\frac{132}{999}\)\(=\)\(\frac{3129}{999}\)
\(5,1\left(2\right)\)\(=\)\(5\frac{12-1}{90}\)\(=\)\(5\frac{11}{90}\)\(=\)\(\frac{461}{90}\)
\(0,02\left(21\right)\)\(=\)\(\frac{221-2}{990}\)\(=\)\(\frac{219}{990}\)
26 tháng 9 2016
\(\left(\frac{\frac{17}{24}.9\frac{1}{2}-3\frac{1}{4}.\frac{17}{24}}{3\frac{1}{2}.2\frac{13}{36}+2\frac{13}{36}.2\frac{3}{4}}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{\frac{17}{24}.\left(9\frac{1}{2}-3\frac{1}{4}\right)}{2\frac{13}{36}.\left(3\frac{1}{2}+2\frac{3}{4}\right)}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{\frac{17}{24}.\left(\frac{19}{2}-\frac{13}{4}\right)}{\frac{85}{36}.\left(\frac{7}{2}+\frac{11}{4}\right)}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{\frac{17}{24}.\frac{19.2-13}{4}}{\frac{85}{36}.\frac{7.2+11}{4}}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{\frac{17}{24}.\frac{25}{4}}{\frac{85}{36}.\frac{25}{4}}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{17}{24}:\frac{85}{36}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{17}{24}.\frac{36}{85}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{3}{10}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{3-5}{10}\right)^{-2}\)
\(=\left(\frac{-1}{5}\right)^{-2}\)
\(=\frac{1}{\left(-\frac{1}{5}\right)^2}=\frac{1}{\frac{\left(-1\right)^2}{5^2}}=\frac{1}{\frac{1}{25}}=25\)
LM
0
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
6 tháng 11 2024
- \(\dfrac{11}{24}\) : \(\dfrac{17}{23}\) - \(\dfrac{11}{24}\) : \(\dfrac{17}{11}\) - \(\dfrac{1}{12}\)
= - \(\dfrac{11}{24}\) x \(\dfrac{23}{17}\) - \(\dfrac{11}{24}\) x \(\)\(\dfrac{11}{17}\) - \(\dfrac{1}{12}\)
= - \(\dfrac{11}{24}\) x (\(\dfrac{23}{17}\) + \(\dfrac{11}{17}\)) - \(\dfrac{1}{12}\)
= - \(\dfrac{11}{24}\) x 2 - \(\dfrac{1}{12}\)
= - \(\dfrac{11}{12}\) - \(\dfrac{1}{12}\)
=- \(\dfrac{12}{12}\)
= - 1
15 tháng 2 2020
\(A=\frac{8\frac{3}{9}\cdot5\frac{1}{4}+3\frac{16}{19}\cdot5\frac{1}{4}}{\left(2\frac{14}{17}-2\frac{1}{34}\right)\cdot34}:\frac{7}{24}\)
\(A=\frac{\left(8\frac{3}{9}+3\frac{16}{19}\right)\cdot5\frac{1}{4}}{\left(2\frac{14}{17}-2\frac{1}{34}\right)\cdot34}\cdot\frac{24}{7}\)
\(A=\frac{\left(\frac{25}{3}+\frac{73}{19}\right)\cdot\frac{21}{4}}{\left(\frac{48}{17}-\frac{69}{34}\right)\cdot34}\cdot\frac{24}{7}\)
\(A=\frac{\frac{694}{57}\cdot\frac{21}{4}}{\frac{27}{34}\cdot34}\cdot\frac{24}{7}=\frac{\left(\frac{2429}{38}\right)}{27}\cdot\frac{24}{7}=\frac{1388}{171}\)
P/S : Số lớn quá
1 1/17 . 1 1/24 . (-5,1)=\(-\frac{121}{80}\)