
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.



......................?
mik ko biết
mong bn thông cảm
nha ................


\(5+x-3=5-\left(x+4\right)\)
\(5+x-3=5-x-4\)
\(x+x=5-4-5+3\)
\(2x=-1\)
\(x=\frac{-1}{2}\)
vay \(x=\frac{-1}{2}\)
\(x-\left(5.\left|-7\right|+3\right)=\left|-8\right|+6-2\)
\(x-\left(5.7+3\right)=8+6-2\)
\(x-38=12\)
\(x=12+38\)
\(x=50\)
vay \(x=50\)
\(\left|x-3\right|+7=0\)
\(\left|x-3\right|=-7\)( ko ton tai)
\(12-3\left|x-1\right|=6\)
\(3\left|x-1\right|=6\)
\(\left|x-1\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-1=2\\x-1=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
vay \(\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)

(x + 1) + (x + 2) + (x + 3 )+ ... + (x + 20) = 250 ( có 20 nhóm )
=> ( x + x + x +...+ x ) + ( 1 + 2 + 3 +...+ 20) = 250 ( có 20 x và 20 số hạng )
=> x . 20 + 20 . 21 : 2 = 250
=> x . 20 + 210 = 250
=> x . 20 = 250 - 210
=> x . 20 = 40
=> x = 40 : 20
x = 2

+ ) \(\left(x-4\right)\left(6-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\6-x=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=4\\x=6\end{cases}}\)
+ ) \(\left(2x-1\right)^2=25\)
\(\left(2x-1\right)^2=5^2\)Hoặc \(\left(2x-1\right)^2=\left(-5\right)^2\)
\(\Rightarrow\orbr{\begin{cases}2x-1=5\\2x-1=-5\end{cases}\Rightarrow\orbr{\begin{cases}2x=6\\2x=-4\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=-2\end{cases}}}\)
+ ) \(\left(x\div6\right)^5=243\)
\(\left(x\div6\right)^5=3^5\)
\(\Rightarrow x\div6=3\)
\(\Leftrightarrow x=18\)
(x+1)^2=(x+1)^0=1
suy ra x+1 = -1 hoặc 1
suy ra x bằng -2 hoặc 0
(x+1)2=(x+1)0
(x+1)2=1
\(\Rightarrow\hept{\begin{cases}x+1=1\\x+1=-1\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x=0\\x=-2\end{cases}}\)