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27 tháng 9

cccc\(\rarr\rho\larr\begin{cases}\rho\chi\delta\vartheta\Phi|_{\placeholder{}}^{\underset{\text{\placeholder{}}}{\overset{\underrightarrow{\overrightarrow{455\vartheta\varkappa\varpi}}}{\xrightarrow{}}}}\\ \placeholder{}\end{cases}\) ccccccccc

5 tháng 8 2016

\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}=3\)

5 tháng 8 2016

\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}=\frac{2^2.78}{104}=\frac{2^2.2.39}{2^3.13}=\frac{2^3.39}{2^3.13}=3\)

26 tháng 10 2018

a)\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}\left(11+5\right)}{3^9.2^4}=\frac{3.16}{2^4}=\frac{3.2^4}{2^4}=3\)

b)\(B=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}\left(13+65\right)}{2^8.2^3.13}=\frac{2^{10}.78}{2^{11}.13}=3\)

c)\(C=\frac{4^9.36+64^4}{16^4.100}=\frac{2^{18}.2^2.3^2+2^{24}}{2^{16}.2^2.5^2}=\frac{2^{20}\left(3^2+2^4\right)}{2^{18}.5^2}=\frac{2^2.25}{25}=4\)

27 tháng 9 2020

a) Ta có: 

\(A=\frac{3^{10}\cdot11+3^{10}\cdot5}{3^0\cdot2^4}\)

\(A=\frac{3^{10}\left(11+5\right)}{1\cdot16}\)

\(A=\frac{3^{10}\cdot16}{16}=3^{10}\)

b) Ta có:

\(B=\frac{2^{10}\cdot13+2^{10}\cdot65}{28\cdot104}\)

\(B=\frac{2^{10}\cdot13\cdot\left(1+5\right)}{2^2\cdot7\cdot2^3\cdot13}\)

\(B=\frac{2^{10}\cdot6\cdot13}{2^5\cdot7\cdot13}=\frac{2^{11}\cdot3\cdot13}{2^5\cdot7\cdot13}\)

\(B=\frac{2^6\cdot3}{7}=\frac{192}{7}\)

27 tháng 9 2019

a, 410.815=220.245=265

b,415.530=230.530=(2.5)30=1030

c, \(\frac{2^{10^{ }}.13+2^{10^{ }}.65}{2^{8^{ }}.104}\)

=\(\frac{2^{10}\left(13+65\right)}{2^8.2^2.26}\) =\(\frac{2^{10}.78}{2^{10}.26}\) =\(\frac{78}{26}\)=3

28 tháng 11 2016

\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)

\(=\frac{2^{10}.\left(13+65\right)}{2^8.104}\)

\(=\frac{2^{10}.78}{2^8.104}\)

\(=\frac{2^8.2^2.78}{2^8.104}\)

\(=\frac{2^8.4.78}{2^8.104}\)

\(=\frac{2^8.312}{2^8.104}\)

\(=\frac{2^8.3.104}{2^8.104}=3\)