HL
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K
Khách
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LD
3
3 tháng 7 2019
\(2^x\cdot5=120\)
\(\Rightarrow2^x=24\)
\(\Rightarrow x=???\)
LT
2
NL
1
VN
1
4 tháng 7 2017
/x+4/15/-/-3,75/=-/-2,15/
/x+4/15/-15/4=-\(\frac{43}{20}\)
x+4/15=\(\frac{43}{20}+\frac{15}{4}\)
x+4/15=59/10
x=59/10-4/15
x=\(5\frac{19}{30}\)
12 tháng 1 2022
Complete the sentences.
16. This box is too heavy for Tom and me. Could you help __us_________to lift it, please?
17. What beautiful roses! Who gave ___it___________to you?
18. My soup is tasteless. Can you pass ___me___________the salt, please?
19. Have you seen my keys? I can't find ____it__________anywhere.
20. There is a new girl in your class, do you know _____her_________?
BC
4
TT
25 tháng 8 2020
Ta có : \(S=\frac{989898.89-898989.98}{2^3+3^4+4^5+...+2014^{2015}}\)
\(=\frac{98\cdot10101\cdot89-89\cdot10101\cdot98}{2^3+3^4+4^5+...+2014^{2015}}\)
\(=\frac{10101\cdot\left(98\cdot89-89\cdot98\right)}{2^3+3^4+4^5+....+2014^{2015}}\)
\(=\frac{10101\cdot0}{2^3+3^4+4^5+....+2014^{2015}}=0\)
Vậy \(S=0\)
NH
25 tháng 8 2020
\(S=\frac{989898.89-898989.98}{2^3+3^4+4^5+...+2014^{2015}}\)
\(=\frac{98\cdot10101\cdot89-89\cdot10101\cdot98}{2^3+3^4+4^5+...+2014^{2015}}\)
\(=\frac{10101\cdot\left(98\cdot89-89\cdot98\right)}{2^3+3^4+4^5+...+2014^{2015}}\)
\(=\frac{10101\cdot0}{2^3+3^4+4^5+...+2014^{2015}}\)
\(=0\)
VA
25 tháng 7 2016
Đặt \(A=\frac{5}{2.4}+\frac{5}{4.6}+\frac{5}{6.8}+..+\frac{5}{100.102}\)
\(\frac{2}{5}A=\frac{2}{2.4}+\frac{2}{4.6}+\frac{3}{6.8}+...+\frac{2}{100.102}\)
\(\frac{2}{5}A=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{100}-\frac{1}{102}\)
\(\frac{2}{5}A=\frac{1}{2}-\frac{1}{102}\)
\(A=\frac{25}{51}:\frac{2}{5}\)
\(A=\frac{125}{102}\)
Ủng hộ mk nha !!! *_*
S
26 tháng 7 2016
\(\text{Đ}\text{ặt}:A=\frac{5}{2.4}+\frac{5}{4.6}+\frac{5}{6.8}+..+\frac{5}{100.102}\)
\(\frac{2}{5}A=\frac{2}{2.4}+\frac{2}{4.6}+\frac{3}{6.8}+...+\frac{2}{100.102}\)
\(\frac{2}{5}A=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{100}-\frac{1}{102}\)
\(\frac{2}{5}A=\frac{1}{2}-\frac{1}{102}\)
\(A=\frac{25}{51}:\frac{2}{5}\)
\(A=\frac{125}{102}\)
NL
1
I need it because I have an exam coming up.
I don't want to fail Literature