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x+5/6=20/27
x=20/27-5/6
x=-5/54
vậy............
7/8:x=1/6
x=7/8:1/6
x=21/4
vậy//////
a) \(x+\frac{5}{6}=\frac{8}{9}\cdot\frac{5}{6}\)
\(\Rightarrow x+\frac{5}{6}=\frac{20}{27}\)
\(\Rightarrow x=\frac{20}{27}-\frac{5}{6}\)
\(\Rightarrow x=-\frac{5}{54}\)
Vậy \(x=-\frac{5}{54}\)
b) \(\frac{7}{8}:x=\frac{1}{2}-\frac{1}{3}\)
\(\Rightarrow\frac{7}{8}:x=\frac{1}{6}\)
\(\Rightarrow x=\frac{7}{8}:\frac{1}{6}\)
\(\Rightarrow x=\frac{21}{4}\)
Vậy \(x=\frac{21}{4}\)
X = 6 \(\times\) 8 + 6 \(\times\) 2 - 5 \(\times\) 10
X = 6 \(\times\) ( 8 + 2) - 5 \(\times\) 10
X = 6 \(\times\) 10 - 5 \(\times\) 10
X = 10 \(\times\) (6-5)
X = 10 \(\times\) 1
X = 10
A = (90:9 + 64) \(\times\) (6 \(\times\) 6 - 4 \(\times\)9)
A = (90 : 9 + 64) \(\times\)(36 - 36)
A = (90:9 + 64) \(\times\) 0
A = 0
X = 6 x 8 + 6 x 2 - 5 x 10
X = 48 + 12 - 50
X = 10
A = ( 90 : 9 + 64 ) x ( 6 x 6 - 4 x 9 )
A = ( 10 + 64 ) x ( 36 - 36)
A = 74 x 0
A = 0
a,=(3+5+7+...+99) x (5-5)
=(3+5+7+...+99)x0
= 0
b, =(64+71-35)x8
=100x8
=800
K MK NHA PẠN
A = (a x 7 + a x 8 - a x 15) : (1 + 2 + 3 + ........ + 10)
A = [a x ( 7 + 8 - 15 )] : [ ( 1 + 9 ) + ( 2 + 8 ) + ( 3 + 7 ) + ( 4 + 6 ) + 5 ]
A = [a x 0] : [ 10 x 4 + 5 ]
A = 0 : 45
A = 0
B = (18 - 9 x 2) x (2 + 4 + 6 + 8 + 10)
B = (18 - 18) x [ ( 2 + 8 ) + ( 4 + 6 ) + 10 ]
B = 0 x [10 x 3]
B = 0 x 30
B = 0
#Hok_tốt
B = (18 - 9 x 2) x (2 + 4 + 6 + 8 + 10)
B = (18 - 18) x 30
B = 0 x 30
=> B = 0
Câu a:
3 x 9 + 18 x 2 + 2 x 9 + 9
= 3 x 9 + 9 x 2 x 2 + 2 x 9 + 9 x 1
= 9 x (3 + 4 + 2 + 1)
= 9 x (7 + 2 + 1)
= 9 x (9+ 1)
= 9 x 10
= 90
Câu c:
44 x 5 + 18 x 10 + 20 x 5
= 44 x 5 + 18 x 2 x 5 + 20 x 5
= 5 x (44+ 36 + 20)
= 4 x (80 + 20)
= 4 x 100
= 400
Câu d
(18 - 9 x 2) x (2+4+6+..+10)
= (18 - 18) x (2+4+6+..+10)
= 0 x (2+4+6+...+10)
= 0
Câu e:
(7 x 8 - 56):(2+4+6+8+112)
= (56 -56):(2+4+6+8+112)
= 0:(2+4+6+8+112)
= 0
Câu f:(2+125+6+145+112)x(42 - 6 x 7)
=(2+125+6+145+112)x(42-42)
= (2+125+6+145+112)x0
= 0
a. 53 + 8 x 53 +53
=53 + 424 + 53
=477 + 53= 530
\(A=\left(a\text{x}7+a\text{x}8-a\text{x}15\right):\left(1+2+3+...+10\right)\)
\(A=\left(a\text{x}\left(7+8-15\right)\right):\left(1+2+3+...+10\right)\)
\(A=\left(a\text{x}0\right):\left(1+2+3+..+10\right)\)
\(A=0:\left(1+2+3+...+10\right)\)
\(A=0\)
\(B=\left(18-9\text{x}2\right)\text{x}\left(2+4+6+8+10\right)\)
\(B=\left(18-18\right)\text{x}\left(2+4+6+8+10\right)\)
\(B=0\text{x}\left(2+4+6+8+10\right)\)
\(B=0\)
a) (128+1276+262+324)x(64-8x8)
=(128+262) + (1276+324)x(64-8x8)
=1600+390=1990
a) = (128+276+262+324) x ( 64 - 64)
= (...) x 0
= 0
b)= ( 8 x 0) x ( ....)
= 0 x (....)
=0
mấy chỗ (....) là viết như đề bài nha!
k mk nha!^^