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a) \(\frac{58}{19}+\frac{13}{17}+\frac{35}{43}+\frac{119}{19}+\frac{8}{43}\)
\(=\frac{13}{17}+\left(\frac{58}{19}+\frac{119}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)\)
\(=\frac{13}{17}+\frac{204}{19}+1\)
\(=\frac{1808}{133}\)
b) \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+\frac{13}{4}\)
\(=\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{13}{4}\)
\(=\frac{-5}{7}.1+\frac{13}{4}\)
\(=\frac{71}{28}\)
c) \(\frac{146}{13}-\left(\frac{21}{7}+\frac{68}{13}\right)\)
\(=\left(\frac{164}{13}-\frac{68}{13}\right)+3\)
\(=\frac{135}{13}\)
d) \(\frac{2}{7}.\frac{21}{4}-\frac{2}{7}.\frac{13}{4}\)
\(=\frac{2}{7}.\left(\frac{21}{4}-\frac{13}{4}\right)\)
\(=\frac{2}{7}.\frac{8}{4}\)
\(=\frac{4}{7}\)
P/s: Mk ko chắc nữa!

\(a,30\cdot6+30\cdot71+20\cdot30\)
=\(30\cdot\left(6+71+20\right)\)
=\(30\cdot97=2910\)
\(b,24\cdot\left(31+119\right)+76\cdot\left(29+121\right)\)
=\(24\cdot150+76\cdot150\)
=\(150\cdot\left(24+76\right)\)
=\(150\cdot100\)
=\(15000\)
\(c,87\cdot23+70\cdot87+43\cdot93\)
=\(87\cdot\left(23+87\right)+43\cdot93\)
=\(87\cdot110+3999\)
=\(9570+3999\)
=13569
a) 15 . 6 . 2 + 3 . 71 . 10 + 20 . 30
= ( 15 . 2 ) . 6 + ( 3 . 10 ) . 71 + 20 . 30
= 30 . 6 + 30 . 71 + 20 . 30
= 30 . ( 6 + 71 + 30 )
= 30 . 107
= 3210
b) 24 . 31 + 24 . 119 + 76 . 29 + 76 . 121
= 24 . ( 31 + 119 ) + 76 . ( 29 + 121 )
= 24 . 150 + 76 . 150
= 150 . ( 24 + 76 )
= 150 . 100
= 15 000
c) 87 . 23 + 43 . 93 + 70 . 87
= 87 . 23 + 70 . 87 + 43 . 93
= 87 . ( 23 + 70 ) + 43 . 93
= 87 . 93 + 43 . 93
= 93 . ( 87 + 43 )
= 93 . 130
= 12 090

a, 119 + 24 + 81
= ( 119 + 81 ) + 24
= 200 + 24
= 224
b, 16 . 6 . 125
= 16 . 125 . 6
= 2000 . 6
= 12000
c, 25 . 104
= 25 . 100 + 25 . 4
= 2500 + 100
= 2600
d, 12 . 19 + 12
= 12 . 19 + 12 . 1
= 12 . ( 19 + 1 )
= 12 x 20
= 240
e, 43 . 27 + 93 . 43 + 57 . 61 + 59 . 57
= 43 . ( 27 + 93 ) + ( 61 + 59 ) . 57
= 43 . 120 + 120 . 57
= 120 . 43 + 120 . 57
= 120 . ( 43 + 57 )
= 120 . 100
= 12000
a/ 199 + 24 + 81
= (119+81) + 24
= 200 + 24
= 224
b/ 16 . 6 . 125
= ( 16 . 125) . 6
= 2000 . 6
= 12000
c/ 25 . 104
= 25 . ( 100 + 4 )
= 25 . 100 + 25 . 4
= 2500 + 100
= 2600
d/43 . 27 + 93 . 43 + 57 . 61 + 59 . 57
= 43 . ( 27 + 93) + 57 . ( 61+ 59)
= 43 . 130 + 57 . 130
= (43 + 57) . 130
= 100 . 130
= 1300

-190 - x= -119 + 219 + 300
-190-x = 400
-x = 400 + 190
-x = 590
=> x = -590
Vậy...

a) = (25+1)-27
= 26-27
= -1
b) = 80 - ( 4.25 - 3. 8)
= 80 - (100-24)
= 80 - 76
= 4
c)= - 25 -15
= -25+ (-15)
= -40
d) =(-219) + ( -219) +30
= -438 +30
= -408
bai 2 : x E { -3;-2;-1;0;1;2;3;4}
tong la:
= -3+(-2)+(-1)+0+1+2+3+4
= (-3 +3)+(-2+2)+(-1+1)+0+4
= 0+0+0+0+4
=4
tick nha
a) (52 + 1) - 9.3 b) 80 - (4.52 - 3. 23) c) [(-18) + (-7)] - 15 d) (-219) - (219) + 12.5
=(25-1)-27 = 80-(4.25 -3 . 8) =(-25) -15 =0+12.5
=24-27 =80-(100-24) =(-25)+(-15) =12.5
=24+(-27) =80-76 =-40 =60
=-3 4
Bài 2: Liệt kê và tính tổng tất caar các số nguyên x thỏa mãn: -4 < x < 5
X THUỘC {-3;(-2);(-1);0;1;2;3;4}
tổng là :
-3+(-2)+(-1)+0+1+2+3+4
=[-3+3]+[-2+2]+[-1+1]+0+4
=0+0+0+0+4
=0+4
=4
a,
A=\(\left(2^9.16+2^8.24\right):2^{11}\)
A=\(\left(2^8.2.16+2^8.24\right):2^{11}\)
A=\(\left(2^8.32+2^8.24\right):2^{11}\)
A=\(\left[2^8.\left(32+24\right)\right]:2^{11}\)
A=\(\left(2^8.56\right):2^{11}\)
A=\(\left(2^8.8.7\right):2^{11}\)
A=\(\left(2^8.2^3.7\right):2^{11}\)
A=\(\left(2^{8+3}.7\right):2^{11}\)
A=\(\left(2^{11}.7\right):2^{11}\)
A=\(2^{11}.7:2^{11}\)
A=\(\left(2^{11}:2^{11}\right).7\)
A=\(1.7\)
A=\(7\)