Question

[Đoàn Phương Linh]

A = \(5\dfrac{17}{39}+\left(4\dfrac{2}{85}-3\dfrac{2}{45}\right)-\left(13\dfrac{19}{85}-\dfrac{11}{45}+\dfrac{4}{39}\right)\)

Answer 1

[Nguyễn Lê Phước Thịnh]

\(=5+\dfrac{17}{39}+4+\dfrac{2}{85}-3-\dfrac{2}{45}-13-\dfrac{19}{85}+\dfrac{11}{45}-\dfrac{4}{39}\)

\(=\left(-4\right)+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}=-4+\dfrac{1}{3}=-\dfrac{11}{3}\)