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\(a=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+...+\frac{1}{45}\)
\(a=\frac{1}{1.3}+\frac{1}{2.3}+\frac{1}{2.5}+\frac{1}{3.5}+...+\frac{1}{5.9}\)
\(a=2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{9.10}\right)\)
\(a=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(a=2\left(\frac{1}{2}-\frac{1}{10}\right)\)
=> \(a=2.\frac{2}{5}\)
=> \(a=\frac{4}{5}\)
\(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{45}\)
\(\Rightarrow\frac{1}{2}A=\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}\right)\cdot\frac{1}{2}\)
\(=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)
\(=\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)
\(=\frac{1}{2}-\frac{1}{10}=\frac{2}{5}\)
\(\Rightarrow A=\frac{2}{5}:\frac{1}{2}=\frac{4}{5}\)

a)\(\left(x+3\right)\times5+1=20\Leftrightarrow5x+15=19\)
\(\Leftrightarrow5x=4\Leftrightarrow x=\frac{4}{5}\)
b)sai đề
c)\(2\frac{3}{7}\times x+1\frac{5}{4}=5\frac{3}{42}\)\(\Leftrightarrow\frac{17}{7}\times x+\frac{9}{4}=\frac{71}{14}\) \(\Leftrightarrow\frac{17}{7}\times x+\frac{63}{28}=\frac{142}{28}\)
\(\Leftrightarrow\frac{17}{7}\times x=\frac{79}{28}\Leftrightarrow x=\frac{17}{7}:\frac{79}{28}\) \(\Leftrightarrow x=\frac{17}{7}\times\frac{28}{79}\Leftrightarrow x=\frac{476}{553}=\frac{68}{79}\)
d)\(10\frac{2}{3}-x:\frac{6}{7}=8\frac{1}{3}-6\frac{2}{7}\Leftrightarrow\frac{32}{3}-x:\frac{6}{7}=\frac{25}{3}-\frac{44}{7}\) \(\Leftrightarrow\frac{224}{21}-x:\frac{6}{7}=\frac{75}{21}-\frac{132}{21}\Leftrightarrow-\frac{57}{21}-\frac{224}{21}\)
\(\Leftrightarrow-x:\frac{6}{7}=-\frac{281}{21}\Leftrightarrow-x=-\frac{281}{21}\times\frac{6}{7}\) \(\Leftrightarrow-x=-\frac{1686}{147}\Leftrightarrow x=\frac{562}{49}=11\frac{23}{49}\)
a) ( x + 3 ) × 5 + 1 = 20 ⇔ 5 x + 15 = 19 (x+3)×5+1=20⇔5x+15=19 ⇔ 5 x = 4 ⇔ x = 4 5 ⇔5x=4⇔x= 5 4 b)sai đề c) 2 3 7 × x + 1 5 4 = 5 3 42 2 7 3 ×x+1 4 5 =5 42 3 ⇔ 17 7 × x + 9 4 = 71 14 ⇔ 7 17 ×x+ 4 9 = 14 71 ⇔ 17 7 × x + 63 28 = 142 28 ⇔ 7 17 ×x+ 28 63 = 28 142 ⇔ 17 7 × x = 79 28 ⇔ x = 17 7 : 79 28 ⇔ 7 17 ×x= 28 79 ⇔x= 7 17 : 28 79 ⇔ x = 17 7 × 28 79 ⇔ x = 476 553 = 68 79 ⇔x= 7 17 × 79 28 ⇔x= 553 476 = 79 68 d) 10 2 3 − x : 6 7 = 8 1 3 − 6 2 7 ⇔ 32 3 − x : 6 7 = 25 3 − 44 7 10 3 2 −x: 7 6 =8 3 1 −6 7 2 ⇔ 3 32 −x: 7 6 = 3 25 − 7 44 ⇔ 224 21 − x : 6 7 = 75 21 − 132 21 ⇔ − 57 21 − 224 21 ⇔ 21 224 −x: 7 6 = 21 75 − 21 132 ⇔− 21 57 − 21 224 ⇔ − x : 6 7 = − 281 21 ⇔ − x = − 281 21 × 6 7 ⇔−x: 7 6 =− 21 281 ⇔−x=− 21 281 × 7 6 ⇔ − x = − 1686 147 ⇔ x = 562 49 = 11 23 49 ⇔−x=− 147 1686 ⇔x= 49 562 =11 49 23
tính giá trị biểu thức
A=3/4 nhân a +(b-1/2):2 với a=5/9 và b=5/2
các bn ghi rõ ràng nhé,mình đang cần

Y +2 x y + 3 x y + 4 x y+ ... + 10 x y = 49,5
giupws mik nha nhớ ghi cách giải rõ ràng nha mọi người

y+2xy+3xy+...+10xy=49,5
yx(1+2+3+4+...+10)=49,5
yx45 =49,5
y= 49,5:45
y= 1,1
t tôi ik
`=8/10+3/10`
`=11/10`
\(\dfrac{8}{10}+\dfrac{3}{5}\times\dfrac{1}{2}=\dfrac{8}{10}+\dfrac{3}{10}=\dfrac{11}{10}=1,1\)