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707 - 3( x + 34 ) = 407
=> 3( x + 81 ) = 300
=> x + 81 = 100
=> x = 19
127 + 3( x + 17 ) = ( 47 : 45 )2
=> 3( x + 17 ) = ( 42 )2 - 127
=> 3( x + 17 ) = 256 - 127
=> 3( x + 17 ) = 129
=> x + 17 43
=> x = 26
x - 6 - ( 48 - 24. 2 : 6 - 3 ) = 100
x - 6 - ( 48 - 2 - 3 ) = 100
x - 6 - 43 = 100
x - 49 = 100
x = 149
[ ( 6x - 39 ) : 3 ] . 28 = 5628
( 6x - 39 ) : 3 = 201
6x - 39 = 603
6x = 642
x = 107
Chúc em hok tốt
Study well
\(707-3.(x+3^4)=407\)
\(\Rightarrow\)\(707-3.(x+81)=407\)
\(\Rightarrow\)\(3.(x+81)=707-407\)
\(\Rightarrow\)\(3.\left(x+81\right)=300\)
\(\Rightarrow\)\(\left(x+81\right)=300:3\)
\(\Rightarrow\)\(\left(x+81\right)=100\)
\(\Rightarrow\) \(x=100-81\)
Xin lỗi vì tôi có việc bận nên tí nữa sẽ làm tiếp
\(\Rightarrow\) \(x=19\)

S= - 32\(\left(\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+...+\frac{1}{868}\right)\)
S = - 32\(\left(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{28.31}\right)\)
S = - 3\(\left(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{28.31}\right)\)
S = -3\(\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{28}-\frac{1}{31}\right)\)
S = -3 \(\left(1-\frac{1}{31}\right)\)
S = -3\(.\frac{30}{31}\)
S = -90/31
1/3S=-(1/1*4+1/4*7+1/7*10+...+1/28*31)=-(1/1-1/4+1/4-1/7+1/7-1/10+...+1/28-1/31)=-(1/1-1/31)=-30/31
=>S=(-30/31):1/3=-90/31

b) <=> 4(10+x) = 3(17+x)
40+4x=51+3x
4x-3x=51-40
x=11
c) <=> 7.(40+x) = 6 .(17+x)
280+7x =102 + 6x
7x-6x=102-280
x=-178
a) 7/x=x/28
=)7*28=x*x
=)196=x^2
=)14^2=x^2
= )x=14
k cho mih di roi mih giai tiep cho nha

Ta có : \(5\frac{8}{17}\div X+\left(-\frac{1}{17}\right)\div X+3\frac{1}{17}\div17\frac{1}{3}=\frac{4}{17}\)
Nên: \(\left(5\frac{8}{17}+\left(-\frac{1}{17}\right)\right)\div X+\frac{52}{17}\div\frac{52}{3}=\frac{4}{17}\)
\(5\frac{7}{17}\div X+\frac{52}{17}\times\frac{3}{52}=\frac{4}{17}\)
\(\frac{92}{17}\div X+\frac{3}{17}=\frac{4}{17}\)
\(\frac{92}{17}\div X=\frac{4}{17}-\frac{3}{17}\)
\(\frac{92}{17}\div X=\frac{1}{17}\)
\(X=\frac{92}{17}\div\frac{1}{17}\)
\(X=92\)
Vậy \(X=92\)
\(5\frac{8}{17}:x+\left(-\frac{1}{17}\right):x=\frac{52}{51}\)
\(\left(5\frac{8}{17}+-\frac{1}{17}\right):x=\frac{52}{51}\)
\(\frac{92}{17}:x=\frac{52}{51}\)
\(X=\frac{92}{17}:\frac{52}{51}=\frac{69}{13}\)

Sửa đề :v hình như vậy mới làm được
\(2\frac{2}{9}-x=\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}\)
\(\frac{20}{9}-x=\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+\frac{2}{42}+\frac{2}{56}+\frac{2}{72}\)
\(\frac{20}{9}-x=2\left[\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}\right]\)
\(\frac{20}{9}-x=2\left[\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{8}-\frac{1}{9}\right]\)
\(\frac{20}{9}-x=2\left[\frac{1}{3}-\frac{1}{9}\right]\)
\(\frac{20}{9}-x=2\cdot\frac{2}{9}\)
\(\frac{20}{9}-x=\frac{4}{9}\Leftrightarrow x=\frac{16}{9}\)

a) 7.28=x.x
=> 196=x2
=> \(\left(\pm14\right)^2=x^2\)
=> x=\(\pm14\)
b) DK: x≠-17
pt<=> 4.(10+2)=6.(17+x)
=> 4.12=17.6+6x
=> 48-102=6x
=>-66=6x
=>x=-11
c) 7.(x+40)=6.(17+x)
=> 7x+280=102+6x
=> 7x-6x=102-280
=> x=-178
Giải:
a) \(\dfrac{7}{x}=\dfrac{x}{28}\)
\(\Leftrightarrow x^2=196\)
\(\Leftrightarrow x=\pm\sqrt{196}=\pm14\)
Vậy ...
b) \(\dfrac{10+2}{17+x}=\dfrac{3}{4}\)
\(\Leftrightarrow40+8=51+3x\)
\(\Leftrightarrow3x=40+8-51=-3\)
\(\Leftrightarrow x=-\dfrac{3}{3}=-1\)
Vậy ...
c) \(\dfrac{40+x}{17+x}=\dfrac{6}{7}\)
\(\Leftrightarrow280+7x=102+6x\)
\(\Leftrightarrow7x-6x=102-280\)
\(\Leftrightarrow x=-178\)
Vậy ...

Ta có: A = 3 + 32 + 33 + ... + 3100
=> 3A = 32 + 33 + 34 + ... + 3101
=> 3A - A = 3101 - 3
=> 2A = 3101 - 3
=> 2A + 3 = 3101
=> x = 101
\(2A=3^2+3^3+...+3^{101}\)
\(2A-A=3^2-3^2+3^3-3^3+...+3^{101}-3\)
\(A=3^{101}-3\)
\(2.3^{101}-6+3=3^x\)
\(3.\left(2.3^{100}-1\right)=3^x\)

\(\left(x-3\right)^{17}=\left(x-3\right)^{117}\)
\(\Rightarrow\orbr{\begin{cases}x-3=\pm1\\x-3=0\end{cases}}\)
\(\Rightarrow x\in\left\{2;3;4\right\}\)
(X-3)17=(X-3)117
(X-3)117-17
(X-3)100
X=3-3
X=0
Mình ko bit sai hay đúng bạn tìm hiểu nhé

c: 2|x-3|=500
=>|x-3|=250
=>x-3=250 hoặc x-3=-250
=>x=253 hoặc x=-247
d: x-17=-8+(-17)
=>x-17=-25
hay x=-8
3x - 17 = 28
3x = 28 + 17
3x = 45
x = 45 : 3
x = 15
Vậy x = 15
\(3.x-17=28\)
\(3.x=28+17\)
\(3.x=45\)
\(x=45:3\)
\(x=15\)
Vậy \(x=15.\)