tìm x
25-(30+x)=x-(27-8)
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Ta có :
25 - ( 30 + x ) = x - ( 27 - 8 )
25 - 30 - x = x - 27 + 8
x + x = 25 - 30 + 27 - 8
2x = 14
x = 14 : 2
x = 7
25 - ( 30 + x ) = x - ( 27 - 8 )
25 - 30 - x = x - 19
25 + (-30)-x = x - 19
-5-x = x - 19
x = -5 - ( x - 19 )
x = -5 - x + 19
x = 14 - x
x + x = 14
2x = 14
x = 14 : 2
x = 7
Vậy x = 7
a) x - (17 - 8) = 5 + (10 - 3x)
x - 17 + 8 = 5 + 10 - 3x
x + 3x = 5 + 10 + 17 - 8
4x = 24
x = 24 : 4
x = 6
b) 25 - (30 + x) = x - (27 - 8)
25 - 30 - x = x - 27 + 8
-x - x = -27 + 8 - 25 + 30
-2x = -14
x = (-14) : (-2)
x = 7
c) (x - 12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 -18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
d) 9 - 25 = (7 - x) - (25 + 7)
9 - 25 = 7 - x - 25 - 7
x = 7 - 25 - 7 - 9 +25
x = -9
a, bổ sung đề
\(\dfrac{29-x}{21}+1+\dfrac{27-x}{23}+1+\dfrac{25-x}{25}+1+\dfrac{23-x}{27}+1+\dfrac{21-x}{29}+1=0\)
\(\Leftrightarrow\dfrac{50-x}{21}+\dfrac{50-x}{23}+\dfrac{50-x}{25}+\dfrac{50-x}{27}+\dfrac{50-x}{29}=0\)
\(\Leftrightarrow\left(50-x\right)\left(\dfrac{1}{21}+\dfrac{1}{23}+\dfrac{1}{25}+\dfrac{1}{27}+\dfrac{1}{29}\ne0\right)=0\Leftrightarrow x=50\)
x-(17-8)=5+(10-3x)
=>x-9 = 5+10-3x = 15-3x
=> x+3x = 15+9
=> 4x = 24
=> x = 24 : 4 = 6
25-(30+x)=x-(27-8)
=> 25-30-x=x-19
=> -5-x=x-19
=> x+x = -5+19 = 14
=> 2x=14
=> x=14:2 =7
k mk nha
a. x - (17 - 8) = 5 + (10 - 3x)
=> x - 9 = 5 + 10 - 3x
=> x + 3x = 15 + 9
=> 4x = 24
=> x = 6
b. 25 - (30 + x) = x - (27 - 8)
=> 25 - 30 - x = x - 19
=> -x -x = -19 + 30 - 25
=> -2x = -14
=> x = 7
c. (x - 12) - 15 = (20 - 7) - (18 + x)
=> x - 12 - 15 = 13 - 18 - x
=> x + x = 13 - 18 + 12 + 15
=> 2x = 22
=> x = 11
a) Ta có: \(\left(-12\right)-\left|13-x\right|=-21\)
\(\Leftrightarrow-\left|x-13\right|-12=-21\)
\(\Leftrightarrow-\left|x-13\right|=-9\)
\(\Leftrightarrow\left|x-13\right|=9\)
\(\Leftrightarrow\left[{}\begin{matrix}x-13=9\\x-13=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=22\\x=4\end{matrix}\right.\)
Vậy: \(x\in\left\{22;4\right\}\)
b) Ta có: \(8\le\left|x\right|< 9\)
\(\Leftrightarrow\left|x\right|=8\)
\(\Leftrightarrow x\in\left\{8;-8\right\}\)
Vậy: \(x\in\left\{8;-8\right\}\)
c) Ta có: \(x-\left(-25+x\right)=13-x\)
\(\Leftrightarrow x+25-x-13+x=0\)
\(\Leftrightarrow x+12=0\)
hay x=-12
Vậy: x=-12
d) Ta có: \(\left(15-30\right)+x=x-\left(27-\left|-8\right|\right)\)
\(\Leftrightarrow x-15=x-\left(27-8\right)\)
\(\Leftrightarrow x-15-x+19=0\)
\(\Leftrightarrow-4=0\)(vô lý)
Vậy: \(x\in\varnothing\)
a)x-13=-5+8
x-13=3
x=3+13
x=16 hoặc -10
b)|x-2|=|-5|
|x-2|=5|
|x|=5+2
|x|=7
x=7 hoặc -7
c)25-(30+x)=x-(27-8)
25-(30+x)=x-19
...còn lại mình bó tay
d)bó tay luôn
25-(30+x)=x-(27-8)
25-30-x=x-19
(-5)-x=x-19
x+x=19+(-5)
x.2=14
x=14:2
x=7
TICK mình nha!!
25 - (30 + x) = x - (27 - 8)
25 - (30 + x) = x - 19
25 - 30 - x = x - 19
-5 - x = x - 19
-x - x = -19 + 5
-2x = -14
x = -14 : (-2)
x = 7
vậy____
25-(30+x)=x-(27-8)
=> 25-30-x=x-19
=>-5-x=x-19
=>-5+19=x+x
=>14=2x
=>x=7