4/3.(-2/7)+4/3:(-7/5)
giups minh vs sap thi r 1 tieng nua thi r
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NK
9 tháng 3 2023
\(a,-\dfrac{12}{16}-\left(\dfrac{3}{4}-x\right)=-\dfrac{5}{3}\)
\(\dfrac{3}{4}-x=-\dfrac{12}{16}-\left(-\dfrac{5}{3}\right)\)
\(\dfrac{3}{4}-x=\dfrac{11}{12}\)
\(x=\dfrac{3}{4}-\dfrac{11}{12}\)
\(x=-\dfrac{1}{6}\)
\(b,x-\dfrac{3}{7}:\dfrac{9}{14}=-\dfrac{7}{3}\)
\(x-\dfrac{3}{7}=-\dfrac{7}{3}\times\dfrac{9}{14}\)
\(x-\dfrac{3}{7}=-\dfrac{3}{2}\)
\(x=-\dfrac{3}{2}+\dfrac{3}{7}\)
\(x=-\dfrac{15}{14}\)
\(c,-\dfrac{3}{4}x+\dfrac{5}{8}x=\dfrac{1}{3}\)
\(\left(-\dfrac{3}{4}+\dfrac{5}{8}\right)x=\dfrac{1}{3}\)
\(-\dfrac{1}{8}x=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\left(-\dfrac{1}{8}\right)\)
\(x=-\dfrac{8}{3}\)
GO
0
18 tháng 12 2018
Có: 7-3.\(\frac{-1}{4}^2\)
= 7-3. \(\frac{1}{16}\)
= 7- \(\frac{3}{16}\)
= \(\frac{112}{16}\)-\(\frac{3}{16}\)
= \(\frac{109}{16}\)
2
6 tháng 5 2022
`@`Bảng tần số:
\begin{array}{|c|c|c|}\hline \text{Giá trị (x)}&2&3&4&5&6&7&8&9&10&\\\hline \text{Tần số (n)}&3&5&4&4&4&3&3&2&1&N=29\\\hline\end{array}
`@` Mốt của dấu hiệu là: `3 ( n = 5)`
23 tháng 4 2022
There are many traffic problem in the city where I live. Firstly, there are too many people using the roads. Secondly, there are too many vehicles on the road that leads to traffic jams. Finally, many roads are narrow and bumpy. Therefore, I think we should obey the traffic rules and traffic signs as well. Moreover, carefulness is very necessary.
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21 tháng 4 2019
a,\(\frac{1}{2}+\frac{3}{4}-\frac{3}{4}+\frac{4}{5}\)
=\(\frac{1}{2}+\frac{3}{4}+\frac{-3}{4}+\frac{4}{5}\)
=\(\left(\frac{3}{4}+\frac{-3}{4}\right)+\frac{1}{2}+\frac{4}{5}\)
= \(0+\frac{1}{2}+\frac{4}{5}=\frac{13}{10}\)
Nhiều quá bạn ơi
NT
2
15 tháng 12 2017
A=\(\dfrac{1}{4}\)+\(\dfrac{1}{4^2}\)+...+\(\dfrac{1}{4^{99}}\)
4A=1+\(\dfrac{1}{4}\)+\(\dfrac{1}{4^2}\)+...+\(\dfrac{1}{4^{98}}\)
4A-A=(1+\(\dfrac{1}{4}\)+..+\(\dfrac{1}{4^{98}}\))-(\(\dfrac{1}{4}\)+\(\dfrac{1}{4^2}\)+...+\(\dfrac{1}{4^{99}}\))
3A=1-\(\dfrac{1}{4^{99}}\)
A=
\(\frac{4}{3}.\left(-\frac{2}{7}\right)+\frac{4}{3}:\left(-\frac{7}{5}\right)\)
\(=\frac{4}{3}.\left(-\frac{2}{7}\right)+\frac{4}{3}.\left(-\frac{5}{7}\right)\)
\(=\frac{4}{3}.\left[\left(-\frac{2}{7}\right)+\left(-\frac{5}{7}\right)\right]\)
\(=\frac{4}{3}.\left(-1\right)=-\frac{4}{3}\)