\(\frac{3^2}{2}-(4,5-\frac{13}{2})\)
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BT
3
NN
14 tháng 4 2022
0,12 x 55 x 3 + 1,8 x 4,5 x 2
=0,12 x 3 x 55 + 1,8 x2 x 4,5
= 0,36 x 55 + 3,6 x 4,5
= 3,6 x 5,5 + 3,6 x 4,5
=3,6 x ( 5,5 + 3,5)
= 3,6 x 10
= 36
LL
1
28 tháng 6 2021
`a)-4/9(5/6*90%-8:0,32)`
`=-4/9(5/6*9/10-8:8/25)`
`=-4/9(3/4-25)`
`=-4/9*(-97)/4=97/9`
`b)(2/5)^2+5 1/2.(4,5-2)+(2^3)/(-4)`
`=4/25+11/2*5/2+8/(-4)`
`=4/25+55/4-2`
`=1191/100`
HH
1
NT
2
LT
3
6 tháng 8 2020
\(\frac{4}{x-3}+\frac{5}{x+3}-\frac{13-9x^2}{x^2-9}\)
ĐKXĐ : \(x\ne\pm3\)
\(=\frac{4}{x-3}+\frac{5}{x+3}-\frac{13-9x^2}{\left(x+3\right)\left(x-3\right)}\)
\(=\frac{4\left(x+3\right)}{\left(x+3\right)\left(x-3\right)}+\frac{5\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}-\frac{13-9x^2}{\left(x+3\right)\left(x-3\right)}\)
\(=\frac{4x+12}{\left(x+3\right)\left(x-3\right)}+\frac{5x-15}{\left(x+3\right)\left(x-3\right)}-\frac{13-9x^2}{\left(x+3\right)\left(x-3\right)}\)
\(=\frac{4x+12+5x-15-13+9x^2}{\left(x+3\right)\left(x-3\right)}\)
\(=\frac{9x^2+9x-16}{\left(x+3\right)\left(x-3\right)}=\frac{9x^2+9x-16}{x^2-9}\)
VN
20 tháng 1 2023
a)
\(11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{18}{7}-\dfrac{68}{13}\)
\(=\left(\dfrac{146}{13}-\dfrac{68}{13}\right)-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
b)
\(\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
Y
20 tháng 1 2023
\(a,11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{68}{13}-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
\(b,\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
\(\frac{3^2}{2}-\left(4,5-\frac{13}{2}\right)\)
\(=\frac92-\left(\frac92-\frac{13}{2}\right)\)
\(=\frac92-\frac92+\frac{13}{2}\)
\(=\frac{13}{2}\)
\(\frac{3}{2}^{2} = \frac{9}{4}\)
\(4 , 5 = \frac{9}{2}\)
suy ra
\(\frac{9}{4} - \left(\right. \frac{9}{2} - \frac{13}{2} \left.\right)\) \(= \frac{9}{4} - \frac{\left(\right. 9 - 13 \left.\right)}{2}\) \(= \frac{9}{4} - \frac{- 4}{2}\) \(= \frac{9}{4} + \frac{4}{2}\) \(= \frac{9}{4} + \frac{8}{4} = \frac{17}{4}\)
vậy
\(\frac{17}{4}\)