Tìm x biết:
\(\frac{27^x}{3^x}=81\)
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\(\frac{1}{81}.27^x=3^x\Rightarrow\frac{1^2}{9^2}=\frac{3^x}{27^x}\)\(\Rightarrow\left(\frac{1}{9}\right)^2 =\left(\frac{1}{9}\right)^x\)\(\Rightarrow X=2\)
=>\(\frac{1}{3^4}\cdot\left(3^3\right)^x=3^x\)
=>\(\frac{3^{3x}}{3^4}=3^x\)
=>\(3x-4=x\)
=>\(3x=x+4\)
=>\(2x=4=>x=2\)
\(2^{x-1}=16\)
\(2^{x-1}=2^4\)
\(\Rightarrow x-1=4\)
\(x=4+1\)
\(x=5\)
Vậy \(x=5\)
b) \(\frac{\left(-3\right)^x}{81}=-27\)
\(\left(-3\right)^x=-27.81\)
\(\left(-3\right)^x=-2187\)
\(\left(-3\right)^x=\left(-3\right)^7\)
\(\Rightarrow x=7\)
Vậy \(x=7\)
a)\(\left(\frac{-1}{3}\right)^3\cdot x=\frac{1}{81}\) \(< =>\frac{-1}{27}x=\frac{1}{81}\)\(< =>x=\frac{-1}{3}\)
a) Ta có: \(\frac{x^7}{81}=27\)
\(\Rightarrow x^7=27.81=2187\)
Mà \(2187=3^7\) \(\Rightarrow x^7=3^7\Leftrightarrow x=3\)
Vậy x = 3
b) Ta có: \(\frac{x^8}{9}=729\)
\(\Rightarrow x^8=729.9=6561\)
Mà \(6561=3^8\) \(\Rightarrow x^8=3^8\Leftrightarrow x=3\)
Vậy x = 3
CHÚC BẠN HỌC TỐT
a) \(2^{x-1}.3=48\)
\(2^{x-1}=16\)
\(2^{x-1}=2^4\)
\(x-1=4\)
\(x=5\)
b.
\(\frac{\left(-3\right)^x}{81}=-27\)
\(\frac{\left(-3\right)^x}{3^4}=\left(-3\right)^3\)
\(\frac{\left(-3\right)^x}{\left(-3\right)^4}=\left(-3\right)^3\)
\(\left(-3\right)^x=\left(-3\right)^4.\left(-3\right)^3\)
\(\left(-3\right)^x=\left(-3\right)^7\)
x=7
a)\(\left(\frac{3}{5}\right)^5.x=\left(\frac{3}{7}\right)^7\)
\(x=\left(\frac{3}{7}\right)^7\div\left(\frac{3}{7}\right)^5\)
\(x=\left(\frac{3}{7}\right)^2\)
\(x=\frac{9}{49}\)
Vậy...
b)\(\left(-\frac{1}{3}\right)^3.x=\left(\frac{1}{3}\right)^4\)
\(\left(-\frac{1}{3}\right)^3.x=\left(-\frac{1}{3}\right)^4\)
\(x=\left(-\frac{1}{3}\right)^4\div\left(\frac{-1}{3}\right)^3\)
\(x=-\frac{1}{3}\)
Vậy...
c)\(\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
=>\(x-\frac{1}{2}=\frac{1}{3}\)
\(x=\frac{1}{3}+\frac{1}{2}\)
\(x=\frac{5}{6}\)
Vậy...
d)\(\left(x+\frac{1}{4}\right)^4=\left(\frac{2}{3}\right)^4\)
=>\(x+\frac{1}{4}=\frac{2}{3}\)
\(x=\frac{2}{3}-\frac{1}{4}\)
\(x=\frac{5}{12}\)
Vậy...
Phù, mãi mới xong, tk cho mk nha bn
Bài 2:
a) \(\frac{x}{-27}=\frac{-3}{x}\Leftrightarrow-\frac{x}{27}=-\frac{3}{x}\Leftrightarrow-x.x=\left(-27\right).\left(-3\right)\Leftrightarrow-x^2=-81\Leftrightarrow\orbr{\begin{cases}x=9\\x=-9\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=9\\x=-9\end{cases}}\)
b) \(\frac{-9}{x}=\frac{-x}{\frac{4}{49}}\Leftrightarrow-\frac{9}{x}=-\frac{49x}{4}\Leftrightarrow-9.4=-x.49x\Leftrightarrow-36=-49x^2\Leftrightarrow\orbr{\begin{cases}x=\frac{6}{7}\\x=-\frac{6}{7}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{6}{7}\\x=-\frac{6}{7}\end{cases}}\)
\(\Rightarrow\frac{27^x}{3^x}=\frac{\left(3^3\right)^x}{3^3}=\frac{3^{3x}}{3^3}=3^4\)
33x=34:33
33x=3
<=> 3x=1
x=1:3
x=1/3
\(\frac{27^x}{3^x}\)=81
Ta có:27x=27x27x27x...x27 (x thừa số 27)
3x=3x3x3x3x...x3(x thừa số 3)
=>\(\frac{27^x}{3^x}\)=27x27x27x27x...27(x thừa số 27):3x3x3x3x...x3(x thừa số 3)
=9x9x9x9x...x9(x thừa số 9)
mà 81=92
=> x=2
Vậy x=2