12 x 13 x 14 x 15 x 16 x a = 41932a0
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11 x 12 + 12 x 13 + 13 x 14 + 14 x 15 + 15 x 16 + 16 x 17 + 17 x 18 + 18 x 19 + 19 x 20 + 20 x 21
= 12 x ( 11 + 13 ) + 14 x ( 13 + 15 ) + 16 x ( 15 + 17 ) + 18 x ( 17 + 19 ) + 20 x 21
= 12 x 24 + 14 x 28 + 16 x 32 + 18 x 36 + 420
= 288 + 392 + 512 + 648 + 420
= ( 288 + 392 ) + ( 512 + 648 ) + 420
= 680 + 1160 + 420
= 1840 + 420
= 2260
tk nha
=
Ta có:
11 x 12 + 12 x 13 + 13 x 14 + 14 x 15 + 15 x 16 + 16 x 17 + 17 x 18 + 18 x 19 + 19 x 20 + 20 x 21
= 12 x ( 11 + 13 ) + 14 x ( 13 + 15 ) + 16 x ( 15 + 17 ) + 18 x ( 17 + 19 ) + 20 x 21
= 12 x 24 + 14 x 28 + 16 x 32 + 18 x 36 + 420
= 288 + 392 + 512 + 648 + 420
= ( 288 + 392 ) + ( 512 + 648 ) + 420
= 680 + 1160 + 420
= 1840 + 420
= 2260
#Mạt Mạt#
\(\frac{x+22}{11}+\frac{x+23}{12}=\frac{x+24}{13}+\frac{x+25}{14}\)
\(\Leftrightarrow\left(\frac{x+22}{11}+1\right)+\left(\frac{x+23}{12}+1\right)=\left(\frac{x+24}{13}+1\right)+\left(\frac{x+25}{14}+1\right)\)
\(\Leftrightarrow\frac{x+33}{11}+\frac{x+35}{12}=\frac{x+37}{13}+\frac{x+39}{14}\)
\(\Leftrightarrow\frac{x+33}{11}+\frac{x+35}{12}-\frac{x+37}{13}-\frac{x+39}{14}=0\)
\(\Leftrightarrow\frac{2184\cdot\left(x+33\right)+2002\cdot\left(x+35\right)-1848\cdot\left(x+37\right)-1716\cdot\left(x+39\right)}{24024}=0\)
\(\Leftrightarrow2184x+72072+2002x+70070-1848x-68376-1716x-66924=0\)
\(\Leftrightarrow622x+6842=0\)
\(\Leftrightarrow x=-11\)
a ) x = 19 20 x = 19 20 b ) x = 83 12 x = − 37 12
c ) x = 31 12 x = − 25 12 d ) x = 13 4 x = − 7 12
10 x 11 = 110
11 x 12 = 132
12 x 13 = 156
13 x 14 = 182
14 x 15 = 210
15 x 16 = 240
Ai mk mk lại!
x=11 suy ra 12=x+1 thay vào A ta có:
A=x^17- (x+1)x^16 + (x+1)x^15 - (x+1)x^14 + .....- (x+1)x^2+(x+1)x -1
= x^17 - x^17 -x^16 + x^16 + x^15 - x^15 - x^14 +.....- x^3 -x^2 + x^2 +x -1
= x-1= 11-1=10
Giải:
Ta có:
\(\dfrac{x+2002}{16}+\dfrac{x+2003}{15}+\dfrac{x+2004}{14}+\dfrac{x+2005}{13}+\dfrac{x+2006}{12}=-5\)
\(\Leftrightarrow\dfrac{x+2002}{16}+\dfrac{x+2003}{15}+\dfrac{x+2004}{14}+\dfrac{x+2005}{13}+\dfrac{x+2006}{12}+5=0\)
\(\Leftrightarrow\dfrac{x+2002}{16}+1+\dfrac{x+2003}{15}+1+\dfrac{x+2004}{14}+1+\dfrac{x+2005}{13}+1+\dfrac{x+2006}{12}+1=0\)
\(\Leftrightarrow\dfrac{x+2002+16}{16}+\dfrac{x+2003+15}{15}+\dfrac{x+2004+14}{14}+\dfrac{x+2005+13}{13}+\dfrac{x+2006+12}{12}=0\)
\(\Leftrightarrow\dfrac{x+2018}{16}+\dfrac{x+2018}{15}+\dfrac{x+2018}{14}+\dfrac{x+2018}{13}+\dfrac{x+2018}{12}=0\)
\(\Leftrightarrow\left(x+2018\right)\left(\dfrac{1}{16}+\dfrac{1}{15}+\dfrac{1}{14}+\dfrac{1}{13}+\dfrac{1}{12}\right)=0\)
Vì \(\dfrac{1}{16}+\dfrac{1}{15}+\dfrac{1}{14}+\dfrac{1}{13}+\dfrac{1}{12}\ne0\)
\(\Leftrightarrow x+2018=0\)
\(\Leftrightarrow x=-2018\)
Vậy ...
12 x 13 x 14 x 15 x 16 x a = 41932a0
12 x 13 x 14 x 15 x 16 x 8 = 4193280
vậy a = 8
Ta có :
12 x 13 x 14 x 15 x 16 = (3 x 3 x 4 x 5) x 14 x 16 x 13
Vì 3 x 3 x 4 x 5 = 12 x 15
=> 9 x 20 x 14 x 16 x 13
=> Tích trên chia hết cho 9
Vì vậy tổng các chữ số của 41932a0 phải chia hết cho 9
4 + 1 + 9 +3 + 2 +0 = 19
=> a = 8
Thử : 12 x 13 x 14 x15 x 16 x 8 = 4193280