2(x+45)-54=-56
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![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a. Ta có: $1953=3^2.7.31$
$777=3.7.37$
$\Rightarrow UCLN(1953, 777) = 3.7=21$
b. Đề khó hiểu quá. Bạn xem lại/
Bài 2: Thiếu dấu giữa các số. Bạn xem lại.
![](https://rs.olm.vn/images/avt/0.png?1311)
42-56+33-(33-56+42)
=42-56+33-33+56-42
=0
54-(45-30+54)-30+5
=54-45+30-54-30+5
=-40
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=\left(4^5\cdot10\cdot5^6+25^5\cdot2^8\right):\left(2^8\cdot5^4+5^7\cdot2^5\right)\)
\(B=\dfrac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)
\(B=\dfrac{\left(2^2\right)^5\cdot2\cdot5\cdot5^6+\left(5^2\right)^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)
\(B=\dfrac{2^{11}\cdot5^7+5^{10}\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)
\(B=\dfrac{2^8\cdot5^7\cdot\left(2^3\cdot1+5^3\cdot1\right)}{2^5\cdot5^4\cdot\left(2^3\cdot1+5^3\cdot1\right)}\)
\(B=\dfrac{2^8\cdot5^7}{2^5\cdot5^4}\)
\(B=\dfrac{2^3\cdot5^3}{1\cdot1}\)
\(B=\left(2\cdot5\right)^3\)
\(B=10^3\)
\(B=1000\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(45-34-11\right)\times\left(56+54+87\right)\)
\(=0\times\left(56+54+87\right)\)
\(=0\)
tíc mình nha
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1; - (-66) + 34 + (-73) - 27 + 99
= 66 + 34 - 73 - 27 + 99
= (66 + 34) - (73 + 27) + 99
= 100 - 100 + 99
= 0 + 99
= 99
2; 54 - (45 - 30 + 54) - 30 + 5
= 54 - 45 + 30 - 54 - 30 + 5
= (54 - 54) + (30 - 30) - (45 - 5)
= 0 + 0 - 40
= - 40
Ta có: \(2\left(x+45\right)-54=-56\)
=>\(2\left(x+45\right)=-56+54=-2\)
=>x+45=-1
=>x=-46
2(x+45)-54=-56
2(x+45) = -56 + 54
2(x+45) = (-2)
(x+45) = (-2) + 2
(x+45) = 0
x = 0 -45
x = -45