334.(-24) + 24 .234
giúp mình vs ạ
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a) (-24) + 18 + 24 + (-28)
= (-24 + 24) + (18 - 28)
= 0 - 28
= -28
b) (-32) . 234 + 234
= 234 . (-32 + 1)
= 234 . (-31)
= -7254
a, (-24) + 18 + 24 +(-28)
= (-24) + 24 - (28 - 18)
= 0 - 10
= - 10
b, (-32) x 234 + 234
= - 234 x ( 32 - 1)
= -234 x 31
= - 7254
a: \(\left(24-234\right)+\left(234-24-77\right)\)
\(=24-234+234-24-77\)
\(=\left(24-24\right)+\left(234-234\right)-77\)
=0+0-77
=-77
b: \(\left(13-135+49\right)-\left(13+49\right)\)
\(=13-135+49-13-49\)
\(=\left(13-13\right)+\left(49-49\right)-135\)
=0+0-135
=-135
c: \(159-524-\left(59-424\right)\)
\(=159-524-59+424\)
\(=\left(159-59\right)-\left(524-424\right)\)
=100-100
=0
d: \(\left(36+79\right)+\left(145-79-36\right)\)
\(=36+79+145-79-36\)
\(=\left(36-36\right)+\left(79-79\right)+145\)
=0+0+145
=145
e: \(334-\left(117+234\right)+\left(42+117\right)\)
\(=334-117-234+42+117\)
\(=\left(334-234\right)+\left(117-117\right)+42\)
=100+0+42
=142
f: \(271-\left[\left(-43\right)+271-\left(-17\right)\right]\)
\(=271+43-271+\left(-17\right)\)
\(=\left(271-271\right)+\left(43-17\right)\)
=0+26
=26
a) \(3\left(x-5\right)+6=36\)
\(\Rightarrow3\cdot\left(x-5\right)=36-6\)
\(\Rightarrow3\cdot\left(x-5\right)=30\)
\(\Rightarrow x-5=10\)
\(\Rightarrow x=10+5\)
\(\Rightarrow x=15\)
b) \(200-8\cdot\left(x+7\right)=24\)
\(\Rightarrow8\cdot\left(x+7\right)=200-24\)
\(\Rightarrow8\cdot\left(x+7\right)=176\)
\(\Rightarrow x+7=\dfrac{176}{8}\)
\(\Rightarrow x+7=22\)
\(\Rightarrow x=22-7\)
\(\Rightarrow x=15\)
c) \(\left(x-890\right)\left(74-x\right)=0\)
+) \(x-890=0\)
\(\Rightarrow x=890\)
+) \(74-x=0\)
\(\Rightarrow x=74\)
d) \(\left(31-x\right)\cdot\left(x-64\right)=0\)
+) \(31-x=0\)
\(\Rightarrow x=31\)
+) \(x-64=0\)
\(\Rightarrow x=64\)
a: gọi d=ƯCLN(n+4;n+5)
=>\(\left\{{}\begin{matrix}n+5⋮d\\n+4⋮d\end{matrix}\right.\)
=>\(n+5-n-4⋮d\)
=>\(1⋮d\)
=>d=1
b: gọi d=ƯCLN(2n+3;2n+1)
=>\(\left\{{}\begin{matrix}2n+3⋮d\\2n+1⋮d\end{matrix}\right.\)
=>\(2n+3-2n-1⋮d\)
=>\(2⋮d\)
mà 2n+3 lẻ
nên d=1
a) \(\dfrac{2x+3}{24}=\dfrac{3x-1}{32}\)
\(\Rightarrow32\left(2x+3\right)=24\left(3x-1\right)\)
\(\Rightarrow64x+96=72x-24\)
\(\Rightarrow8x=120\Rightarrow x=15\)
b) \(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\)
\(\Rightarrow17\left(13x-2\right)=76\left(2x+5\right)\)
\(\Rightarrow221x-34=152x+380\)
\(\Rightarrow69x=414\Rightarrow x=6\)
Ta có : 16=24 24=23.3
UCLN (16,24)=23=8
=> UC(16,24,)=(1,2,4,8)
Tich nha
Ta có:16=24 24=23x3
ƯCLN(16,24)=23=8
=> ƯC(16,24)=(1,2,4,8)
Ta có: 180=22x32x5 234=2x32x13
ƯCLN(180,234)=2x32=18
=> ƯC(60,90,135)=180,234)=(1,2,3,6,9,18)
Ta có:60=22x3x5 90=2x32x5 135=33x5
ƯCLN(60,90,135)=3x5=15
=> ƯC(60,90,135)=(1,3,5,15)
Đây nha bạn.
Chúc bạn học tốt!
\(3\left(x+3\right)=-24\)
\(x+3=-\dfrac{24}{3}\)
\(x+3=-8\)
\(x=-8-3\)
\(x=-11\)
\(334\cdot\left(-24\right)+24\cdot234\)
\(=24\left(-334+234\right)\)
\(=24\cdot\left(-100\right)=-2400\)