Question

[Vũ Khải Minh]

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(\left|-\dfrac{1}{3}\right|-\left(-\dfrac{6}{7}\right)^0+\left(\dfrac{1}{2}\right)^2:2\)

\(=\dfrac{1}{3}-1+\dfrac{1}{4}:2=-\dfrac{2}{3}+\dfrac{1}{8}=\dfrac{-16}{24}+\dfrac{3}{24}=-\dfrac{13}{24}\)

b: \(\left(\dfrac{2}{3}\right)^3+\sqrt{\dfrac{49}{81}}-\left|-\dfrac{7}{3}\right|:3\)

\(=\dfrac{8}{27}+\dfrac{7}{9}-\dfrac{7}{3}\cdot\dfrac{1}{3}\)

\(=\dfrac{8}{27}+\dfrac{7}{9}-\dfrac{7}{9}=\dfrac{8}{27}\)

c: \(\sqrt{\dfrac{25}{49}}+\left(5555\right)^0+\left|-\dfrac{2}{7}\right|\)

\(=\dfrac{5}{7}+1+\dfrac{2}{7}\)

=1+1=2