rút gọn
\(\frac{23.5-23}{4-27}\);
\(\frac{2130-15}{3550-25}\);
\(\frac{1717-101}{2828-404}\)
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Nếu đề là \(\frac{23.5-23}{4-27}\) thì ok :v
\(\frac{23.5-23}{4-27}=\frac{23.5-23}{-23}=\frac{23.\left(5-1\right)}{-23}=\frac{23.4}{-23}=\frac{92}{-23}\)
23-23.5 phần 4-27=23.(1-5)phần -23=23.-4 phần -23=-23.4 phần -23=4
Đáp số 4
\(\frac{23.5-23}{4-27}\)=\(\frac{23.\left(5-1\right)}{-23}\)=\(\frac{92}{-23}\)
a; \(\dfrac{9}{27}\) + \(\dfrac{7}{-49}\)
= \(\dfrac{1}{3}\) - \(\dfrac{1}{7}\)
= \(\dfrac{7}{21}\) - \(\dfrac{3}{21}\)
= \(\dfrac{4}{21}\)
b; - \(\dfrac{12}{10}\) + \(\dfrac{-25}{30}\)
= - \(\dfrac{6}{5}\) - \(\dfrac{5}{6}\)
= -\(\dfrac{36}{30}\) - \(\dfrac{25}{30}\)
= \(\dfrac{-61}{30}\)
c; \(\dfrac{-20}{35}\) + \(\dfrac{-16}{-24}\)
= - \(\dfrac{4}{7}\) + \(\dfrac{2}{3}\)
= - \(\dfrac{12}{21}\) + \(\dfrac{14}{21}\)
= \(\dfrac{2}{21}\)
d; - \(\dfrac{21}{77}\) + \(\dfrac{10}{-35}\)
= - \(\dfrac{3}{11}\) - \(\dfrac{2}{7}\)
= - \(\dfrac{21}{77}\) - \(\dfrac{22}{77}\)
= - \(\dfrac{43}{77}\)
a) \(\frac{2.7.13}{26.35}=\frac{2.7.13}{2.13.7.5}=\frac{1}{5}\)
b) \(\frac{3.5.11.13}{33.35.37}=\frac{3.5.11.13}{3.11.7.5.37}=\frac{13}{259}\)
c) \(\frac{23.5-23}{4-27}=\frac{23.\left(5-1\right)}{-23}=\frac{4}{-1}=-4\)
d) \(\frac{1717-101}{2828+404}=\frac{101.17-101}{404.7+404}=\frac{101.\left(17-1\right)}{404.\left(7+1\right)}=\frac{101.16}{404.8}=\frac{101.2.8}{101.4.8}=\frac{1}{2}\)
\(\frac{23.5-23}{-27}\)
\(=\frac{23.\left(5-1\right)}{-27}\)
\(=\frac{23.4}{-27}\)
\(=\frac{92}{-27}\)
\(=\frac{-92}{27}\)