A=4^2.25^2+32.125/2^3.5^2+49^25.125^10.2^8+5^30.(-7)^49.4^4/16^2.5^29.(-7)^48
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28 tháng 11 2017
\(A=\frac{49^{24}.125^{10}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{48}}\)
\(A=\frac{\left(7^2\right)^{24}.\left(5^3\right)^{10}.2^8-5^{30}.7^{49}.\left(2^2\right)^5}{5^{29}.\left(2^4\right)^2.7^{48}}\)
\(A=\frac{7^{49}.5^{30}.2^8-5^{30}.7^{49}.2^{10}}{5^{29}.2^8.7^{48}}\)
\(A=\frac{7^{48}.5^{30}.2^8\left(1-28\right)}{5^{29}.2^8.7^{48}}\)
\(A=5.\left(-27\right)\)
\(A=-135\)
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4 tháng 10 2021
\(\dfrac{4^2.25^2+32.125}{2^3.5^2}=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}=\dfrac{2^3.5^2\left(2.5^2+2^2.5\right)}{2^3.5^2}=2.5^2+2^2.5=50+20=70\)
\(A=\dfrac{4^2.25^2+32.125}{\dfrac{2^3.5^2+49^{25}.125^{10}.2^8+5^{30}.\left(-7\right)^{49}.4^4}{16^2.5^{29}.\left(-7\right)^{48}}}\)
\(A=\dfrac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^3}{\dfrac{2^3.5^2+\left(7^2\right)^{25}.\left(5^3\right)^{10}.2^8+5^{30}.\left(-7\right)^{49}.\left(2^2\right)^4}{\left(2^4\right)^2.5^{29}.\left(-7\right)^{48}}}\)
\(A=\dfrac{2^4.5^4+2^5.5^3}{\dfrac{2^3.5^2+7^{50}.5^{30}.2^8+5^{30}.\left(-7\right)^{49}.2^8}{2^8.5^{29}.\left(-7\right)^{48}}}\)
\(A=\dfrac{2^4.5^2.\left(5^2+2\right)}{\dfrac{2^3.5^2+7.\left(7^{49}.5^{30}.2^8-7^{49}.5^{30}.2^8\right)}{2^8.5^{29}.7^{48}}}\)
\(A=\dfrac{\dfrac{2^4.5^2.\left(25+2\right)}{2^3.5^2}}{2^8.5^{29}.7^{48}}\)
\(A=\dfrac{2^4.5^2.27}{2^3.5^2}\div2^8.5^{29}.7^{48}\)
\(A=\dfrac{2^4.5^2.3^3}{2^3.5^2.2^8.5^{29}.7^{48}}\)
\(A=\dfrac{27}{2^7.5^{29}.7^{48}}\)
Vậy....
cảm ơn bạn ^w^