1-2/5
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a: \(P=\dfrac{\sqrt{3}\left(2+\sqrt{3}\right)}{\sqrt{3}}+\dfrac{\sqrt{2}\left(\sqrt{2}-1\right)}{1}-\sqrt{3}-\sqrt{2}\)
\(=2+\sqrt{3}+2-\sqrt{2}-\sqrt{3}-\sqrt{2}\)
\(=4-2\sqrt{2}\)
b: \(N=\left(1-\dfrac{\sqrt{5}\left(\sqrt{5}+1\right)}{\sqrt{5}+1}\right)\left(\dfrac{-\sqrt{5}\left(1-\sqrt{5}\right)}{1-\sqrt{5}}-1\right)\)
\(=\left(1-\sqrt{5}\right)\left(-\sqrt{5}-1\right)\)
\(=\left(\sqrt{5}-1\right)\left(\sqrt{5}+1\right)=5-1=4\)
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A = 2^3 + 2^4+ 2^5+ 2^6 + 2^7 + ... + 2^90
2A = 2^4 + 2^5 + 2^6 + 2^7 + 2^8 + .... + 2^90 + 2^100
2A - A = ( 2^4 + 2^5 + 2^6 + 2^7 + 2^8 + .... + 2^90 + 2^100 ) - ( 2^3 + 2^4+ 2^5+ 2^6 + 2^7 + ... + 2^90 )
A = 2^100 - 2^3
B = 1 + 5 + 5^2 + 5^3 + 5^4 + .... + 5^50
5B = 5 + 5^2 + 5^3 + 5^4 + 5^5 + .... + 5^50 + 5^51
5B - B = ( 5 + 5^2 + 5^3 + 5^4 + 5^5 + .... + 5^50 + 5^51 ) - ( 1 + 5 + 5^2 + 5^3 + 5^4 + .... + 5^50 )
4B = 5^51 - 1
B = 5^51 - 1 / 4
a: =>x-2/5=3/4:1/3=3/4*3=9/4
=>x=9/4+2/5=45/20+8/20=53/20
b: =>x-2/3=7/3:4/5=7/3*5/4=35/12
=>x=35/12+2/3=43/12
c: 1/3(x-2/5)=4/5
=>x-2/5=4/5*3=12/5
=>x=12/5+2/5=14/5
d: =>2/3x-1/3-1/4x+1/10=7/3
=>5/12x-7/30=7/3
=>5/12x=7/3+7/30=77/30
=>x=77/30:5/12=154/25
e: \(\Leftrightarrow x\cdot\dfrac{3}{7}-\dfrac{2}{7}+\dfrac{1}{2}-\dfrac{5}{4}x+\dfrac{5}{2}=0\)
=>\(x\cdot\dfrac{-23}{28}=\dfrac{2}{7}-3=\dfrac{-19}{7}\)
=>x=19/7:23/28=76/23
f: =>1/2x-3/2+1/3x-4/3+1/4x-5/4=1/5
=>13/12x=1/5+3/2+4/3+5/4=257/60
=>x=257/65
i: =>x^2-2/5x-x^2-2x+11/4=4/3
=>-12/5x=4/3-11/4=-17/12
=>x=17/12:12/5=85/144
Lời giải chi tiết:
5 – 2 < 4 | 5 – 4 < 2 | 4 + 1 = 5 |
5 – 2 = 3 | 5 – 3 > 1 | 5 – 1 < 5 |
5 – 2 > 2 | 5 – 1 = 4 | 5 – 4 > 0 |
Lời giải chi tiết:
5 – 2 – 1 = 2 | 4 – 2 – 1 = 1 | 3 – 1 – 1 = 1 |
5 – 2 – 2 = 1 | 5 – 1 – 2 = 2 | 5 – 1 – 1 = 3 |
Lời giải chi tiết:
4 < 5 | 1 < 4 | 2 < 3 | 1 = 1 |
2 = 2 | 5 > 2 | 2 < 4 | 5 > 1 |
3 > 1 | 3 = 3 | 2 < 5 | 3 < 5 |
Lời giải chi tiết:
2 + 2 < 5 | 2 + 1 = 1 + 2 | 3 + 1 < 3 + 2 |
2 + 3 = 5 | 2 + 2 > 1 + 2 | 3 + 1 = 1 + 3 |
5 + 0 = 5 | 2 + 0 < 1 + 2 | 1 + 4 = 4 + 1 |
2 + 2 < 5 2 + 1 = 1 + 2 3 + 1 < 3 + 2
2 + 3 = 5 2 + 2 > 1 + 2 3 + 1 = 1 + 3
5 + 0 = 5 2 + 0 < 1 + 2 1 + 4 = 4 + 1
\(1-\dfrac{2}{5}=\dfrac{5}{5}-\dfrac{2}{5}=\dfrac{3}{5}\)
\(1-\dfrac{2}{5}=\dfrac{5}{5}-\dfrac{2}{5}=\dfrac{5-2}{5}=\dfrac{3}{5}\)