Tính bằng cách thuận tiện
5/34 + 9/17 : 1/2 - 1/17
Giúp mình nha
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$#Shả$
`A)=5/17xx(15/34+19/34)`
`=5/17xx1=5/17`
`B)=(13/12+7/12)+1/3`
`=5/3+1/3=2`
a) 3/8 x 14/53 x 8/3
=3/8x8/3x14/53
= 1 x 14/53
=14/53
b) 9/17x1/5+9/17x4/5
=9/17x(1/5+4/5)
=9/17x 5/5
=9/17x1
= 9/17
Li-ke cho mik nhé!
\(\frac{15}{34}-\frac{5}{17}+\frac{19}{34}-\frac{12}{17}\)
\(=\left(\frac{15}{34}+\frac{19}{34}\right)-\left(\frac{5}{17}+\frac{12}{17}\right)\)
\(=1-1=0\)
\(\frac{15}{34}-\frac{5}{17}+\frac{19}{34}-\frac{12}{17}\)
\(=\left(\frac{15}{34}+\frac{19}{34}\right)-\left(\frac{5}{17}+\frac{12}{17}\right)\)
\(=\frac{34}{34}-\frac{17}{17}\)
\(=1-1\)
\(=0\)
`3/7+2/5+4/7`
`=(3/7+4/7)+2/5`
`=1+2/5`
`=5/5+2/5`
`=7/5`
`20/34+4/9+7/17`
`=(20/34+7/17)+4/9`
`=(20/34+14/34)+4/9`
`=34/34+4/9`
`=1+4/9`
`=9/9+4/9`
`=13/9`
`48xx2+96+48xx6`
`=48xx2+48xx2+48xx6`
`=48xx(2+2+6)`
`=48xx10`
`=480`
câu thứ hai thì làm như này em nhé:
\(\dfrac{20}{34}\) + \(\dfrac{4}{9}\) + \(\dfrac{7}{17}\)
= (\(\dfrac{20}{34}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)
= (\(\dfrac{10}{17}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)
= 1 + \(\dfrac{4}{9}\)
= \(\dfrac{13}{9}\)
a) 3/7+5/2+4/7
=(3/7+4/7)+5/2
=1+5/2
=7/2
b)6/8+4/5+1/4
=(6/8+1/4)+4/5
=1+4/5
=9/5
đến đó thôi mệt quá
a; \(\dfrac{3}{7}\) + \(\dfrac{5}{2}\) + \(\dfrac{4}{7}\)
= (\(\dfrac{3}{7}+\dfrac{4}{7}\)) + \(\dfrac{5}{2}\)
= 1 + \(\dfrac{5}{2}\)
= \(\dfrac{2}{2}+\dfrac{5}{2}\)
= \(\dfrac{7}{2}\)
b; \(\dfrac{6}{8}\) + \(\dfrac{4}{5}\) + \(\dfrac{1}{4}\)
= \(\dfrac{1}{4}\) + \(\dfrac{4}{5}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{1}{4}\) + \(\dfrac{1}{4}\)) + \(\dfrac{4}{5}\)
= \(\dfrac{2}{4}\) + \(\dfrac{4}{5}\)
= \(\dfrac{1}{2}\) + \(\dfrac{4}{5}\)
= \(\dfrac{5}{10}\) + \(\dfrac{8}{10}\)
= \(\dfrac{13}{10}\)
Câu 1: Tìm x:
a) 2/5× x =(thiếu đề)
8/7: x =4/5
x=8/7:4/5
x=10/7
Câu 2: Tính bằng cách thuận tiện nhất
5/9× 8/17 + 4/9 × 8/17
=(5/9+4/9)x8/17
=1x8/17=8/17
\(\dfrac{5}{34}+\dfrac{9}{17}:\dfrac{1}{2}\)
\(=\dfrac{5}{34}+\dfrac{18}{17}\)
\(=\dfrac{5}{34}+\dfrac{36}{34}\)
\(=\dfrac{41}{34}\)
\(\dfrac{5}{34}+\dfrac{9}{17}:\dfrac{1}{2}\)
\(=\dfrac{5}{34}+\dfrac{9}{17}\times2\)
\(=\dfrac{5}{34}+\dfrac{18}{17}\)
\(=\dfrac{5}{34}+\dfrac{36}{34}=\dfrac{41}{34}\)