Tính tổng:
A= 1+2+2^2+......+2^62
B=1+3+3^2+3^3+......+3^20
C=1+4+4^2+4^3+.....+4^49
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a, S=1+2+22+23+................+263
\(\Rightarrow\)2S=2+22+23+24+.................+264
\(\Rightarrow\)2S-S=(2+22+23+.................+264) - (1+2+22+...............+263)
\(\Rightarrow\)S=264-1
b,S=1+3+32+.................+320
\(\Rightarrow\)3S=3+32+33+...............+321
\(\Rightarrow\)3S-S=(3+32+33+................+321) - (1+3+32+.................+320)
\(\Rightarrow\)2S=321-1
\(\Rightarrow\)S=\(\frac{3^{21}-1}{2}\)
c,Tương tự:4S=4+42+43+...............+450
\(\Rightarrow\)4S-S=450-1
\(\Rightarrow S=\frac{4^{50}-1}{3}\)
S=1+2^2+2^3+.........+2^63
S=2^0+2^1+2^2+.....+2^63
2S=2x(20+21+22+...+263)
2S=21+22+23+24+......+264
2S-S=(21+22+23+24+..........+264)\(-\)(20+21+22+....+263)
1S=264\(-\)20
S=264\(-\)1
Các câu khác tương tự
câu b nhân S với 3
Câu c nhân S với 4
Cơ số bao nhiêu thì nhân với bấy nhiêu
a) 3A=1.2.3 + 2.3.3 + 3.4.3 +... + n.(n+1).3
=1.2.(3-0) + 2.3.(4-1) + ... + n.(n+1).[(n+2)-(n-1)]
=[1.2.3+ 2.3.4 + ...+ (n-1).n.(n+1)+ n.(n+1)(n+2)] - [0.1.2+ 1.2.3 +...+(n-1).n.(n+1)]
=n.(n+1).(n+2)
=>S=[n.(n+1).(n+2)] /3
b)
Nhân 4 vào hai vế ta được:
4A = 4.[1.2.3 + 2.3.4 + 3.4.5 + … + (n – 1).n.(n + 1)]
4A = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + … + (n – 1).n.(n + 1).4
4A = 1.2.3.4 + 2.3.4.(5 – 1) + 3.4.5.(6 – 2) + … + (n – 1).n.(n + 1).[(n + 2) – (n – 2)]
4A = 1.2.3.4 + 2.3.4.5 – 1.2.3.4 + 3.4.5.6 – 2.3.4.5 + … + (n – 1).n(n + 1).(n + 2) – (n – 2).(n – 1).n.(n + 1)
4A = (n – 1).n(n + 1).(n + 2)
A = (n – 1).n(n + 1).(n + 2) : 4.
3A=1.2.3 + 2.3.3 + 3.4.3 +... + n.(n+1).3
=1.2.(3-0) + 2.3.(4-1) + ... + n.(n+1).[(n+2)-(n-1)]
=[1.2.3+ 2.3.4 + ...+ (n-1).n.(n+1)+ n.(n+1)(n+2)] - [0.1.2+ 1.2.3 +...+(n-1).n.(n+1)]
=n.(n+1).(n+2)
=>S=[n.(n+1).(n+2)] /3
Ta có ; K = \(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+.....+\frac{1}{45}\)
\(=1+\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+....+\frac{2}{90}\)
\(=1+\left(\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+.....+\frac{2}{9.10}\right)\)
\(=1+2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+.....+\frac{1}{9.10}\right)\)
\(=1+2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=1+2\left(\frac{1}{2}-\frac{1}{10}\right)\)
\(=1+1-\frac{1}{5}\)(nhân phá ngoặc)
\(=2-\frac{1}{5}\)< 2
Vậy K = \(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+.....+\frac{1}{45}\)< 2
a) S=1+2+22+...+263
2S=2+22+23+...+264
2S-S=S=264-1
các câu khác tương tự
Tính tổng:a)3+3/5+3/25+3/125+3/625
b)M=4/3.7+4/7.11+4/11.15+...+8/95.99
c)N=1/2+1/6+1/12+1/20+...+1/90
Ta có : \(M=\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+.....+\frac{4}{95.99}\)
\(=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+......+\frac{1}{95}-\frac{1}{99}\)
\(=\frac{1}{3}-\frac{1}{99}\)
\(=\frac{32}{99}\)
a) \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).\left(1-\frac{1}{5}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.\frac{4}{5}\)
\(=\frac{1}{5}\)
b) \(\left(1-\frac{3}{4}\right).\left(1-\frac{3}{7}\right).\left(1-\frac{3}{10}\right)........\left(1-\frac{3}{97}\right).\left(1-\frac{3}{100}\right)\)
\(=\frac{1}{4}.\frac{4}{7}.\frac{7}{10}.......\frac{94}{97}.\frac{97}{100}\)
\(=\frac{1}{100}\)
A = 1 × 2 × 3 + 2 × 3 × 4 + .....+ 48 × 49 × 50
ta có 4 x A = 1 x 2 x 3 x 4 + 2 x 3 x 4 x (5 -1) + .....+ 48 × 49 × 50 x (51 - 47)
= 1 x 2 x 3 x 4 + 2 x 3 x 4 x 5 - 1 x 2 x 3 x 4 + ... + 48 x 49 x 50 x 51 - 47 x 48 x 49 x 50
= 48 x 49 x 50 x 51
suy ra A = (48 x 49 x 50 x 51) : 4
= 12 x 49 x 50 x 51
nhớ k cho mik nha rùi mik lm nốt cho
A = 1 × 2 × 3 + 2 × 3 × 4 + .....+ 48 × 49 × 50
ta có 4 x A = 1 x 2 x 3 x 4 + 2 x 3 x 4 x (5 -1) + .....+ 48 × 49 × 50 x (51 - 47)
= 1 x 2 x 3 x 4 + 2 x 3 x 4 x 5 - 1 x 2 x 3 x 4 + ... + 48 x 49 x 50 x 51 - 47 x 48 x 49 x 50
= 48 x 49 x 50 x 51
suy ra A = (48 x 49 x 50 x 51) : 4
= 12 x 49 x 50 x 51
\(A=1+2+2^2+...+2^{62}\)
\(\Rightarrow2A=2.\left(1+2+2^2+...+2^{62}\right)\)
\(\Rightarrow2A=2+2^2+2^3+...+2^{63}\)
\(\Rightarrow2A-A=2+2^2+2^3+...+2^{63}-\left(1+2+2^2+...+2^{62}\right)\)
\(\Rightarrow A=2+2^2+2^3+...+2^{63}-1-2-2^2-...-2^{62}\)
\(\Rightarrow A=2^{63}-1\)
\(B=1+3+3^2+3^3+...+3^{20}\)
\(\Rightarrow3B=3+3^2+3^3+...+3^{21}\)
\(\Rightarrow3B-B=3+3^2+3^3+...+3^{21}-1-3-3^2-...3^{20}\)
\(\Rightarrow2B=3^{21}-1\)
\(\Rightarrow B=\frac{3^{21}-1}{2}\)
\(C=1+4+4^2+...+4^{49}\)
\(\Rightarrow4C=4+4^2+4^3+...+4^{50}\)
\(\Rightarrow4C-C=4+4^2+4^3+...+4^{50}-1-4-4^2-...-4^{49}\)
\(\Rightarrow3C=4^{50}-1\)
\(\Rightarrow C=\frac{4^{50}-1}{3}\)