101x9,4-9,4+25x2,4 /250%x125%x32
DẤU GẠCH / NÀY LÀ GẠCH PHÂN SỐ
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(1/2003+1/2004+1/2005) / (2/2003+2/2004+2/2005)
= (1/2003+1/2004+1/2005) / 2(1/2003+1/2004+1/2005)
= 1/2
\(A=\frac{2}{3}+\frac{1}{3}+\frac{1}{15}+\frac{1}{75}+\frac{1}{375}+\frac{1}{1875}\)
\(A=\left(\frac{2}{3}+\frac{1}{3}\right)+\frac{1}{15}+\frac{1}{75}+\frac{1}{375}+\frac{1}{1875}\)
\(A=1+\left(\frac{5}{75}+\frac{1}{75}\right)+\frac{1}{375}+\frac{1}{1875}\)
\(A=1+\frac{6}{75}+\frac{1}{375}+\frac{1}{1875}\)
\(A=1+\left(\frac{150}{1875}+\frac{1}{1875}\right)+\frac{1}{375}\)
\(A=1+\frac{151}{1875}+\frac{1}{375}\)
\(A=1+\left(\frac{151}{1875}+\frac{5}{1875}\right)\)
\(A=1+\frac{156}{1875}\)
\(A=\frac{1875}{1875}+\frac{156}{1875}\)
\(A=\frac{677}{625}\)
\(A=\frac{2}{3}+\frac{1}{3}+\frac{1}{15}+\frac{1}{75}+\frac{1}{375}+\frac{1}{1875}\)
\(\Leftrightarrow A=\left(\frac{2}{3}+\frac{1}{3}\right)+\left(\frac{1}{15}+\frac{1}{75}\right)+\left(\frac{1}{375}+\frac{1}{1875}\right)\)
\(\Leftrightarrow A=1+\left(\frac{5}{75}+\frac{1}{75}\right)+\left(\frac{5}{1875}+\frac{1}{1875}\right)\)
\(\Leftrightarrow A=1+\frac{6}{75}+\frac{6}{1875}\)
\(\Leftrightarrow A=1+\frac{2}{25}+\frac{2}{625}\)
\(\Leftrightarrow A=1+\left(\frac{2}{25}+\frac{2}{625}\right)\)
\(\Leftrightarrow A=1+\left(\frac{50}{625}+\frac{2}{625}\right)\)
\(\Leftrightarrow A=1+\frac{52}{625}\)
\(\Leftrightarrow A=\frac{677}{625}\)
x + 3/4 = 9/8
x= 9/8 - 3/4 (Ta quy đồng 1: 9/8 - 6/8)
x = 2/8 = 1/4.
viết sao à
\(\dfrac{101\times9,4-9,4+25\times2,4}{250\%\times125\%\times32}\)
\(=\dfrac{9,4\left(101-1\right)+60}{2,5\times1,25\times32}=\dfrac{940+60}{100}=10\)