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DT
2 tháng 4

A=1x3+2x4+3x5+...+99x100

A=(1x3+3x5+...+99x101)+(2x4+4x6+...+98x100)

đặt S=1x3+3x5+...+99x101

=>6S=6x(1x3+3x5+...+99x101)

=1x3x(5+1)+3x5x(7-1)+...+97x99x(101-95)+99x101x(103-97)

=1x3x5+1x3x1+3x5x7-1x3x5+....+97x99x101-95x97x99+99x101x103-97x99x101

=1x3x1+99x101x103

=>S=(3+99x101x103):6=171650

=>C=171650+(2x4+4x6+...+98x100)

đặt A=2x4+4x6+...+98x100

=>6A=6x(2x4+4x6+...+98x100)

=>6A=2x4x6+4x6x(8-2)+...+96x98x(100-94)+98x100x(102-96)

=2x4x6+4x6x8-2x4x6+...+96x98x100-94x96x98+98x100x102-96x98x100

=98x100x102

=>A=98x100x102:6=166600

=>A=166600+171650

=>A=338250

21 tháng 8 2015

\(a,\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{43.45}=\frac{5}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{43.45}\right)=\frac{5}{3}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{43}-\frac{1}{45}\right)=\frac{5}{3}.\frac{44}{45}=\frac{44}{27}\)

12 tháng 3 2022

=1(2+1)+2(3+1)+3(4+1)+...+100(101+1)

=1.2+1+2.3+2+3.4+3+...+100.101+100

=(1.2+2.3+3.4+..+100.101)+(1+2+3+...+100)

=333300+5000

=338300

2 tháng 7 2018

\(S=1.3+2.4+3.5+...+99.101\)

\(\Rightarrow S=1\left(2+1\right)+2\left(3+1\right)+...+99\left(100+1\right)\)

\(\Rightarrow S=\left(1.2+2.3+...+99.100\right)+\left(1+2+3+...+99\right)\)

Đặt \(A=1.2+2.3+...+99.100\)

\(\Rightarrow3A=1.2.3+2.3.\left(4-1\right)+...+99.100.\left(101-98\right)\)

\(\Rightarrow3S=1.2.3+2.3.4-1.2.3+...+99.100.101-98.99.100\)

\(\Rightarrow S=\frac{99.100.101}{3}\)

Đặt \(B=1+2+3+...+99\)

\(\Rightarrow B=\frac{\left(99+1\right)\left[\left(99-1\right):2+1\right]}{2}\)

\(\Rightarrow B=\frac{100.50}{2}=2500\)

\(\Rightarrow S=A+B=\frac{99.100.101}{3}+2500\)

2 tháng 7 2018

S = 1 x 3 + 2 x 4 + 3 x 5 + ... + 99 x 101

S = ( 1 x 3 + 3 x 5 + ...+ 99 x 101) +  ( 2 x 4 + ...+ 98 x 100)

Đặt A = 1 x 3 + 3 x 5 + ...+ 99 x 101

=> 6 A = 1 x 3 x 6 + 3 x 5 x 6 + ...+ 99 x 101 x 6

6 A = 1 x 3 x ( 5+1) + 3 x 5 x ( 7-1) + ...+ 99 x 101 x ( 103 - 97)

6A = 1 x 3 x 5 + 1 x 3 + 3 x 5 x 7 - 1 x 3 x 5 + ...+ 99 x 101 x 103 - 97 x 99 x 101

6A = ( 1 x 3 + 1 x 3 x 5 + 3 x 5 x 7 +...+ 99 x 101 x 103) - ( 1 x 3 x 5 + ...+ 97 x 99 x 101)

6A = 1 x  3 + 99 x 101 x 103

\(\Rightarrow A=\frac{1.3+99.101.103}{6}=171650\)

Đặt B = 2 x 4 + ...+ 98 x 100

=> 6B = 2 x 4 x 6 + 4 x 6 x 6 + ...+ 98 x 100 x 6

6B = 2 x 4 x 6 + 4 x 6 x ( 8-2) + ...+ 98 x 100 x ( 102 - 96)

6B = 2 x 4 x 6 + 4 x6 x8 - 2x4x6 + ...+ 98x100x102 - 96x98x100

6B = ( 2 x 4 x 6 + 4 x 6 x 8 +...+98x100x102) - ( 2x4x6+...+96x98x100)

6B = 98 x 100 x 102

\(\Rightarrow B=\frac{98.100.102}{6}=166600\)

Thay A;B vào S, có
S = 171 650 + 166 600

S = 338 250

14 tháng 8 2015

có C= 1x3+2x4+3x5+...+18x20

    C= 1x(1+2)+2x(1+3)+3x(1+4)+....+18x(1+19)

    C= 1x1+1x2+1x2+2x3+1x3+3x4+....+1x18+18x19

    C= 1+1x2+2+2x3+3+3x4+....+18+18x19

    C= (1+2+3+4+...+18) + (1x2+2x3+3x4+....+18x19)

    C=  171+ (1x2+2x3+....+18x19)

Đặt A=1x2+2x3+3x4+...+18x19

    3A=1x2x3+2x3x3+3x4x3+....+18x19x3

    3A=1x2x(3-0)+2x3x(4-1)+3x4x(5-2)+.....+18x19x(20-17)

    3A= 1x2x3-0+2x3x4-1x2x3+3x4x5-2x3x4+.....+18x19x20-17x18x19

    3A= 18x19x20

    3A= 6840

     A=2280

Vậy C= 171+2280=2451