Rút gọn hai phân số sau: 121212 / 424242 và 1999999999 / 9999999995.
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\(\frac{121212}{424242}=\frac{121212:10101}{424242:10101}=\frac{12}{42}=\frac{2}{7}\)
\(\frac{1999999999}{9999999995}=\frac{1999999999:1999999999}{9999999995:1999999999}=\frac{1}{5}\)
\(\frac{1999999999}{9999999995}=\frac{1999999999:1999999999}{9999999995:1999999999}=\frac{1}{5}\)
\(\frac{121212}{424242}\)
= \(\frac{12.10101}{42.10101}\)
rút gọn
= \(1\)
ta có \(\frac{121212}{424242}=\frac{121212:60606}{424242:60606}=\frac{2}{7}\)
\(\frac{199.......9}{999.......5}=\frac{199.......9:199.......9}{999.......5:199........9}=\frac{1}{5}\)
\(\frac{121212}{424242}=\frac{121212:10101}{424242:10101}=\frac{12}{42}\)
\(\frac{187187187}{221221221}=\frac{187187187:1001001}{221221221:1001001}=\frac{187}{221}\)
\(\frac{20082008}{20112011}=\frac{20082008:10001}{20112011:10001}=\frac{2008}{2011}\)
\(\frac{199...9}{99...95}\)=\(\frac{199...9:199...9}{99...95:199...9}\)\(\frac{\left(20so9\right)}{\left(20so9\right)}\)
=\(\frac{1}{5}\)
a:\(\dfrac{12}{13}\)
b:\(\dfrac{12}{13}\)
c:\(\dfrac{121}{131}\)
Lời giải:
$\frac{121212}{424242}=\frac{121212:10101}{424242:10101}=\frac{12}{42}=\frac{12:6}{42:6}=\frac{2}{7}$
$\frac{1999999999}{9999999995}=\frac{1999999999}{1999999999\times 5}=\frac{1}{5}$