3/3-1/4*x=0,25
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KS
28 tháng 3 2022
a) 0,25x3/4-0,25x0,25+0,25x1/2
=0,25x(3/4-0,25+1/2)
=0,25x1
=0,25
b) 5,68x8+56,8x0,1+56,8:10
=5,68x8+5,68+5,68
=5,68x(8+1+1)
=5,68x10
=56,8
TN
3
NK
29 tháng 12 2022
\(9\times\left(\dfrac{-1}{3}\right)^3+\dfrac{1}{3}:0,25-5\dfrac{3}{4}=\dfrac{9}{1}\times\left(\dfrac{-1}{27}\right)+\dfrac{1}{3}:\dfrac{1}{4}-\dfrac{23}{4}\)
\(=\left(\dfrac{-9}{27}\right)+\dfrac{4}{3}-\dfrac{23}{4}=\left(\dfrac{-1}{3}\right)+\dfrac{4}{3}-\dfrac{23}{4}=\dfrac{3}{3}-\dfrac{23}{4}=1-\dfrac{23}{4}=\dfrac{4}{4}-\dfrac{23}{4}=\dfrac{-19}{4}\)
B
2 tháng 12 2018
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5 tháng 7 2019
\(\frac{2}{3}\cdot x-\frac{1}{4}\left(1\frac{1}{3}-\frac{3}{4}\right)=0,25\cdot\frac{2}{3}\)
\(\Rightarrow\frac{2}{3}\cdot x-\frac{1}{4}\left(\frac{4}{3}-\frac{3}{4}\right)=\frac{1}{4}\cdot\frac{2}{3}\)
\(\Rightarrow\frac{2}{3}\cdot x-\frac{1}{4}\cdot\frac{7}{12}=\frac{1}{6}\)
\(\Rightarrow\frac{2}{3}.x-\frac{7}{48}=\frac{1}{6}\)
\(\Rightarrow\frac{2}{3}x=\frac{5}{16}\)
\(\Rightarrow x=\frac{15}{32}\)
5 tháng 7 2019
\(\frac{2}{3}\times x-\frac{1}{4}:\left(1\frac{1}{3}-\frac{3}{4}\right)=0,25\times\frac{2}{3}\)
\(\frac{2}{3}\times x-\frac{1}{4}:\left(\frac{4}{3}-\frac{3}{4}\right)=\frac{1}{4}\times\frac{2}{3}\)
\(\frac{2}{3}\times x-\frac{1}{4}:\frac{7}{12}=\frac{1}{6}\)
\(\frac{2}{3}\times x-\frac{3}{7}=\frac{1}{6}\)
\(\frac{2}{3}\times x=\frac{1}{6}+\frac{3}{7}\)
\(\frac{2}{3}\times x=\frac{25}{42}\)
\(x=\frac{25}{42}:\frac{2}{3}\)
\(x=\frac{25}{28}\)
5 tháng 3 2018
\(x-0.25=-\frac{6}{11}\cdot\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\)
\(x-\frac{1}{4}=-\frac{6}{11}\cdot\left(\frac{6}{12}+\frac{9}{12}-\frac{4}{12}\right)\)
\(x-\frac{1}{4}=-\frac{6}{11}\cdot\frac{11}{12}\)
\(x-\frac{1}{4}=-\frac{1}{2}\)
\(x=-\frac{1}{2}+\frac{1}{4}\)
\(x=-\frac{2}{4}+\frac{1}{4}\)
\(x=-\frac{1}{4}\)
Vậy .......
Lời giải:
$\frac{3}{3}-\frac{1}{4}\times x=0,25$
$1-\frac{1}{4}\times x=0,25$
$\frac{1}{4}\times x=1-0,25=0,75$
$x=0,75: \frac{1}{4}=3$