Question

[Nguyễn Khánh Linh]

2/3*x-1/4:(1và1/3-3/4)=0,25*2/3

Answer 1

[Nguyễn Thị Bích Ngọc]

\(\frac{2}{3}\cdot x-\frac{1}{4}\left(1\frac{1}{3}-\frac{3}{4}\right)=0,25\cdot\frac{2}{3}\)

\(\Rightarrow\frac{2}{3}\cdot x-\frac{1}{4}\left(\frac{4}{3}-\frac{3}{4}\right)=\frac{1}{4}\cdot\frac{2}{3}\)

\(\Rightarrow\frac{2}{3}\cdot x-\frac{1}{4}\cdot\frac{7}{12}=\frac{1}{6}\)

\(\Rightarrow\frac{2}{3}.x-\frac{7}{48}=\frac{1}{6}\)

\(\Rightarrow\frac{2}{3}x=\frac{5}{16}\)

\(\Rightarrow x=\frac{15}{32}\)

Answer 2

[Nguyễn Tấn Phát]

\(\frac{2}{3}\times x-\frac{1}{4}:\left(1\frac{1}{3}-\frac{3}{4}\right)=0,25\times\frac{2}{3}\)

\(\frac{2}{3}\times x-\frac{1}{4}:\left(\frac{4}{3}-\frac{3}{4}\right)=\frac{1}{4}\times\frac{2}{3}\)

\(\frac{2}{3}\times x-\frac{1}{4}:\frac{7}{12}=\frac{1}{6}\)

\(\frac{2}{3}\times x-\frac{3}{7}=\frac{1}{6}\)

\(\frac{2}{3}\times x=\frac{1}{6}+\frac{3}{7}\)

\(\frac{2}{3}\times x=\frac{25}{42}\)

\(x=\frac{25}{42}:\frac{2}{3}\)

\(x=\frac{25}{28}\)