\(\dfrac{x+140}{x}\)=70X2+1
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\(\dfrac{140}{x}+5=\dfrac{\left(140+10\right)}{x-1}\left(x\ne0,x\ne1\right)\)
\(\Leftrightarrow\dfrac{140+5x}{x}=\dfrac{150}{x-1}\)
\(\Leftrightarrow\left(x-1\right)\cdot\left(140+5x\right)=150x\)
\(\Leftrightarrow140x+5x^2-140-5x-150x=0\)
\(\Leftrightarrow5x^2-15x-140=0\)
\(\Leftrightarrow x^2-3x-28=0\)
\(\Leftrightarrow\left(x-7\right)\left(x+4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-7=0\\x+4=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=7\left(N\right)\\x=-4\left(N\right)\end{matrix}\right.\)
\(S=\left\{7,-4\right\}\)
ĐK: `x \ne 0 ; x \ne -1`
`140/x+5=150/(x-1)`
`<=>(140+5x)/x=150/(x-1)`
`<=>(140x+5x)(x-1)=150x`
`<=>5x^2+135x-140=150x`
`<=>5x^2-15x-140=0`
`<=>` \(\left[{}\begin{matrix}x=7\\x=-4\end{matrix}\right.\)
Vậy...
Ta có
A = x 5 – 70 x 4 – 70 x 3 – 70 x 2 – 70 x + 29 = x 5 – 71 x 4 + x 4 – 71 x 3 + x 3 – 71 x 2 + x 2 – 71 x + x – 71 + 100 = x 4 ( x – 71 ) + x 3 ( x – 71 ) + x 2 ( x – 71 ) + x ( x – 71 ) + ( x – 71 ) + 100
Vì x = 71 nên x – 71 = 0, thay x – 71 = 0 vào A ta đươc
A = x 4 . 0 + x 3 . 0 + x 2 . 0 + x . 0 + 0 + 100 = 100
Vậy A = 100
Đáp án cần chọn là: C
b) \(-2\dfrac{2}{3}:x=1\dfrac{7}{9}:0.8\\ -\dfrac{8}{3}:x=\dfrac{16}{9}:\dfrac{4}{5}\\ -\dfrac{8}{3}:x=\dfrac{16}{9}.\dfrac{5}{4}\\ -\dfrac{8}{3}:x=\dfrac{20}{9}\\ x=-\dfrac{8}{3}:\dfrac{20}{9}\\ x=-\dfrac{8}{3}.\dfrac{9}{20}\\ x=-\dfrac{6}{5}\)
\(2\dfrac{2}{3}x+3\dfrac{3}{4}x=\dfrac{385}{24}\)
\(\dfrac{8}{3}x+\dfrac{15}{4}x=\dfrac{385}{24}\)
\(x\left(\dfrac{8}{3}+\dfrac{15}{4}\right)=\dfrac{385}{24}\)
\(x\left(\dfrac{32}{12}+\dfrac{45}{12}\right)=\dfrac{385}{24}\)
\(x\left(\dfrac{77}{12}\right)=\dfrac{385}{24}\)
\(x=\dfrac{385}{24}:\dfrac{77}{12}\)
\(x=\dfrac{385}{24}.\dfrac{12}{77}\)
<Bạn tự viết phép tính nha>
\(x=\dfrac{5}{2}\)
Vậy \(x=\dfrac{5}{2}\)
Chúc bn hk tốt!!
Ta có \(\dfrac{x+5}{7}=\dfrac{40}{140}\)
\(\Leftrightarrow\dfrac{x+5}{7}=\dfrac{2}{7}\\ \Leftrightarrow x+5=2\\ \Leftrightarrow x=-3\)
Tương tự : \(\dfrac{-30}{5y+5}=\dfrac{40}{140}\)
\(\Leftrightarrow\dfrac{-6}{y+1}=\dfrac{2}{7}\\ \Leftrightarrow\left(y+1\right)\cdot2=-6\cdot7\\ \Leftrightarrow2y+2=-42\)
\(\Leftrightarrow2y=-44\\ \Leftrightarrow y=-22\)
Vậy..................................
71 + 52,5 x 4 = \(\dfrac{x+140}{x}\)+ 210
71 + 210 = (x + 140) : x + 210
71 = x : x + 140 : x (cùng bỏ trừ đi 210)
71 = 1 + 140 : x
71 - 1 = 140 : x
70 = 140 : x
140 : 70 = x
2 = x
\(a.\left(x\times0,25+1999\right)\times2000=2052\times2000\\ \left(x\times0,25+1999\right)\times2000=4104000\\ x\times0,25+1999=4104000:2000\\ x\times0,25+1999=2052\\ x\times0,25=2052-1999\\ x\times0,25=53\\ x=53:0,25\\ x=212\)
\(71+52,5\times4=\frac{x+140}{x}+210\)
\(71+210=\frac{x+140}{x}+210\)
\(=>\frac{x+140}{x}=71\)
\(71=\frac{142}{2}\)\(\Rightarrow x=142-140=2\)
a)
Theo tính chất của dãy tỉ số bằng nhau, ta có:
\(\dfrac{x}{5}=\dfrac{y}{25}=\dfrac{x+y}{5+25}=\dfrac{60}{30}=2\)
\(\Rightarrow\dfrac{x}{5}=2\Rightarrow x=2\times5=10\)
\(\Rightarrow\dfrac{y}{25}=2\Rightarrow y=2\times25=50\)
Vậy\(\left\{{}\begin{matrix}x=10\\y=50\end{matrix}\right.\)
b)
\(\dfrac{x}{5}=\dfrac{y}{7}\Rightarrow\left(\dfrac{x}{5}\right)^2=\left(\dfrac{y}{9}\right)^3\Rightarrow\dfrac{x}{5}\times\dfrac{x}{5}=\dfrac{x}{5}\times\dfrac{y}{7}=\dfrac{x\times y}{5\times7}=\dfrac{140}{35}=4=\left(2\right)^2\)
\(\Rightarrow\dfrac{x}{5}=2\Rightarrow x=2\times5=10\)
\(\Rightarrow\dfrac{y}{7}=2\Rightarrow y=2\times7=14\)
Vậy \(\left\{{}\begin{matrix}x=10\\y=14\end{matrix}\right.\)
địt mẹ cái thằng ngu hốc cặc
\(\dfrac{x+140}{x}\) = 70 x 2 + 1
\(x\) + 140 = (140 + 1) x \(x\)
\(x\) + 140 = 141 x \(x\)
\(141\) x \(x\) - \(x\) = 140
\(x\) x (141 - 1) = 140
\(x\) x 140 =140
\(x\) = 140 : 140
\(x\) = 1