\(\dfrac{24x101-24}{36x22+72x89}\)= ?
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36 x 22 + 72 x 39
= 36 x 22 + 36 x 2 x 39
= 36 x 22 + 36 x 78
= 36 x (22+78)
= 36 x 100
= 3 600
Sửa đề : \(-\dfrac{19}{37}=\dfrac{19}{37}\)
\(\dfrac{19}{37}-\dfrac{31}{24}-\dfrac{19}{37}+1\dfrac{7}{24}-\dfrac{2}{13}\)
\(=\dfrac{19}{37}-\dfrac{31}{24}+\dfrac{19}{37}+\dfrac{31}{24}-\dfrac{2}{13}\)
\(=\left(\dfrac{19}{37}-\dfrac{19}{37}\right)+\left(-\dfrac{31}{24}+\dfrac{31}{24}\right)-\dfrac{2}{13}=-\dfrac{2}{13}\)
\(=\left(\dfrac{9}{24}+\dfrac{15}{24}\right)-\left(\dfrac{7}{41}+\dfrac{34}{41}\right)+0,75=1-1+0,75=0,75\)
\(\left(\dfrac{18}{37}+\dfrac{19}{37}\right)+\left(\dfrac{8}{24}-\dfrac{47}{24}\right)+\dfrac{2}{3}=\dfrac{37}{37}-\dfrac{13}{8}+\dfrac{2}{3}=\dfrac{1}{24}\)
\(A=\frac{19}{24}-\frac{1}{2}-\frac{1}{3}-\frac{7}{24}\)
\(A=\frac{19}{24}+\frac{-1}{2}+\frac{-1}{3}+\frac{-7}{24}\)
\(A=\left(\frac{19}{24}+\frac{-7}{24}\right)+\frac{-1}{2}+\frac{-1}{3}\)
\(A=\frac{1}{2}+\frac{-1}{2}+\frac{-1}{3}\)
\(A=0+\frac{-1}{3}=\frac{-1}{3}\)
\(B=\frac{7}{24}+\frac{5}{6}+\frac{1}{4}-\frac{3}{7}-\frac{5}{15}\)
\(B=\frac{7}{24}+\frac{5}{6}+\frac{1}{4}+\frac{-3}{7}+\frac{-1}{3}\)
\(B=\left(\frac{49}{168}+\frac{140}{168}+\frac{42}{168}\right)+\left(\frac{-72}{168}+\frac{-56}{168}\right)\)
\(B=\frac{231}{168}+\frac{-128}{168}=\frac{103}{168}\)
Có: \(A=\frac{-1}{3}=\frac{\left(-1\right)\cdot56}{3\cdot56}=\frac{-56}{168}\)
Mặt khác: \(-56< 103\)
\(\Rightarrow\)\(\frac{-56}{168}< \frac{103}{168}\)
\(hay\) \(A< B\)
=(11/24 + 13/24) + (-5/41 - 36/41) + 0.5
= 1 + (-1) + 0.5
= 0 + 0.5
= 0.5
`#3107.101107`
\(\dfrac{24\times101-24}{36\times22+72\times89}\\ =\dfrac{24\times\left(101-1\right)}{36\times22+36\times89\times2}\\ =\dfrac{24\times\left(101-1\right)}{36\times\left(22+178\right)}\\ =\dfrac{24\times100}{36\times200}\\ =\dfrac{2}{3\times2}\\ =\dfrac{2}{6}\\ =\dfrac{1}{3}\)
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