Thực hiện phép tính : ( Tính hợp lí nếu có ). --Nâng Cao--
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
14 tháng 4 2023
5: =5/7(5/11+2/11-14/11)
=5/7*(-7/11)
=-5/11
6: =-5/4(2/11+9/11)+1+3/4
=7/4-5/4=1/2
7: =-5/7(3/13+10/13)+1+5/7
=1
8: =7/4(29/5-9/5)+3+2/13
=3+2/13+7/4*4
=10+2/13
=132/13
11 tháng 3 2022
c: \(=\left(\dfrac{3}{5}+\dfrac{83}{200}-\dfrac{3}{200}\right)\cdot\dfrac{8}{3}\cdot\dfrac{1}{4}=\dfrac{8}{3}\cdot\dfrac{1}{4}=\dfrac{2}{3}\)
g: \(=\dfrac{1}{2}\cdot\dfrac{4}{3}\cdot\dfrac{3}{4}\cdot\dfrac{5}{2}+\dfrac{3}{5}=\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25+12}{20}=\dfrac{37}{20}\)
10 tháng 3 2022
e: \(=\dfrac{21-6}{8}\cdot\dfrac{16}{3}=\dfrac{15}{3}\cdot2=10\)
f: \(=\dfrac{-3\cdot3+7\cdot4}{12}:\dfrac{2\cdot2-5\cdot9}{18}\)
\(=\dfrac{19}{12}\cdot\dfrac{18}{-41}=\dfrac{-57}{82}\)
g: \(=\dfrac{9-8}{10}\cdot\dfrac{5}{2}+1=\dfrac{1}{10}\cdot\dfrac{5}{2}+1=\dfrac{1}{4}+1=\dfrac{5}{4}\)
10 tháng 3 2022
o: \(=\dfrac{3}{4}\cdot\left[\dfrac{1}{5}-\dfrac{4}{7}-\dfrac{3}{5}\cdot\dfrac{-5}{7}\right]=\dfrac{3}{4}\cdot\left(\dfrac{1}{5}-\dfrac{4}{7}+\dfrac{3}{7}\right)\)
\(=\dfrac{3}{4}\cdot\left(\dfrac{1}{5}-\dfrac{1}{7}\right)=\dfrac{3}{4}\cdot\dfrac{2}{35}=\dfrac{3}{70}\)
p: \(=\left[\left(\dfrac{1}{9}\cdot\dfrac{27}{8}\right)\cdot3\right]\cdot\dfrac{-128}{81}=\dfrac{9}{8}\cdot\dfrac{-128}{81}=\dfrac{-16}{9}\)
11 tháng 3 2022
a: \(=\dfrac{3\cdot5-4\cdot7}{35}+\dfrac{4}{5}=\dfrac{15-28+28}{35}=\dfrac{15}{35}=\dfrac{3}{7}\)
e: \(=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{1}{4}\right)\cdot\dfrac{5}{7}=\dfrac{7}{5}-\dfrac{4}{5}\cdot\dfrac{5}{7}=\dfrac{7}{5}-\dfrac{4}{7}=\dfrac{49-20}{35}=\dfrac{29}{35}\)
i: =9/7+5/6-9/7=5/6
\(5:\left(-\dfrac{5}{2}\right)^2+\dfrac{2}{15}\cdot\sqrt{\dfrac{9}{4}}-\left(-2020\right)^0+\left|-0,25\right|\)
\(=5:\dfrac{25}{4}+\dfrac{2}{15}\cdot\dfrac{3}{2}-1+0,25\)
\(=5\cdot\dfrac{4}{25}+\dfrac{3}{15}-0,75\)
\(=\dfrac{4}{5}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=1-\dfrac{3}{4}\)
\(=\dfrac{1}{4}\)
\(5:\left(-\dfrac{5}{2}\right)^2+\dfrac{2}{15}\cdot\sqrt{\dfrac{9}{4}}-\left(-2020\right)^0+\left|-0,25\right|\)
\(=5:\dfrac{25}{4}+\dfrac{2}{15}\cdot\dfrac{3}{2}-1+0,25\)
\(=\dfrac{4}{5}+\dfrac{1}{5}-1+\dfrac{1}{4}\)
\(=1-1+\dfrac{1}{4}\)
\(=\dfrac{1}{4}\)
#kễnh