91-5.(5+x)=61 [195-(3x-27)].39=4212
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LD
2
26 tháng 7 2023
a,91-5(5+x)=61
=>25+5x=91-61=30
=>5x=30-25=5
=>x=1
b,\([\left(x+34\right)-50]\)x2=56
=>(x+34)-50=56:2=28
=>x+34=28+50=78
=>x=78-34=44.
c,1045-\([2015-\left(3x-24\right)]\)=5
=>2015-(3x-24)=1045-5=1040
=>3x-24=2015-1040=975
=>3x=975+24=999
=>x=999:3=333
d,\([195-\left(3x-27\right)]\)x39=4212
=>195-(3x-27)=4212:39=108
=>3x-27=195-108=87
=>3x=87+27=117
=>x=39
e,30-3(x-2)=18
=>30-3x+6=18
=>30-3x=18-6=12
=>3x=30-12=18
=>x=18:3=6
26 tháng 7 2023
a) \(...\Rightarrow5\left(5+x\right)=91-61=30\)
\(\Rightarrow\left(5+x\right)=30:5=6\Rightarrow x=6-5=1\)
b) \(...\Rightarrow\left(x+34\right)-50=56:2=28\)
\(\Rightarrow\left(x+34\right)=28+50=78\Rightarrow x=78-34=44\)
c) \(...\Rightarrow2015-\left(3x-24\right)=1045-5=1040\)
\(\Rightarrow\left(3x-24\right)=2015-1040=975\)
\(\Rightarrow3x=975+24=999\Rightarrow x=999:3=333\)
d) \(...\Rightarrow195-\left(3x-27\right)=4212:39=108\)
\(\Rightarrow\left(3x-27\right)=195-108=87\)
\(\Rightarrow3x=87+27=114\Rightarrow x=114:3=38\)
e) \(...\Rightarrow3\left(x-2\right)=30-18=12\Rightarrow x-2=12:3=4\)
\(\Rightarrow x=4+2=6\)
H9
HT.Phong (9A5)
CTVHS
31 tháng 7 2023
\(\left[195-\left(3x-27\right)\right]\cdot39=4212\)
\(\Rightarrow\left(195-3x+27\right)\cdot39=4212\)
\(\Rightarrow\left(-3x+222\right)\cdot39=4212\)
\(\Rightarrow-3x+222=\dfrac{4212}{39}\)
\(\Rightarrow-3x+222=108\)
\(\Rightarrow3x=222-108\)
\(\Rightarrow3x=114\)
\(\Rightarrow x=\dfrac{114}{3}\)
\(\Rightarrow x=38\)
31 tháng 7 2023
=>[195-(3x-27)]=4212:39=108
=>3x-27=195-108=87
=>3x=27+87=114
=>x=38
H
6 tháng 8 2023
\(\left[195-\left(3x-27\right)\right]\cdot39=4212\\ \Rightarrow195-\left(3x-27\right)=4212:39\\ \Rightarrow195-\left(3x-27\right)=108\\ \Rightarrow3x-27=195-108\\ \Rightarrow3x-27=87\\ \Rightarrow3x=87+27\\ \Rightarrow3x=114\\ \Rightarrow x=114:3\\ \Rightarrow x=38\)
HQ
Hà Quang Minh
Giáo viên
6 tháng 8 2023
\(\left[195-\left(3x-27\right)\right]\cdot39=4212\\ \Leftrightarrow195-\left(3x-27\right)=108\\ \Leftrightarrow3x-27=87\\ \Leftrightarrow3x=114\\ \Leftrightarrow x=38\)
Vậy x = 38.
7 tháng 9 2016
[195-(15x-27).39=4212
195-(15x-27)=4212 : 39
195-(15x-27)=108
15x-27=195-108
15x-27=87
15x=87+27
15x=114
x=114:15
x=38/5
x=7,6
k đúng cho m nha bạn !
15 tháng 7 2018
a) \(1045:\left[215-\left(3x-24\right)\right]=5\)
\(\Rightarrow215-\left(3x-24\right)=1045:5\)
\(\Rightarrow215-\left(3x-24\right)=209\)
\(\Rightarrow3x-24=215-209\)
\(\Rightarrow3x-24=6\)
\(\Rightarrow3x=6+24\)
\(\Rightarrow3x=30\)
\(\Rightarrow x=30:3\)
\(\Rightarrow x=10\)
Vậy x = 10
b) \(\left[195-\left(15x+27\right)\right]\times39=4212\)
\(\Rightarrow195-\left(15x+27\right)=4212:39\)
\(\Rightarrow195-\left(15x+27\right)=108\)
\(\Rightarrow15x+27=195-108\)
\(\Rightarrow15x+27=87\)
\(\Rightarrow15x=87-27\)
\(\Rightarrow15x=60\)
\(\Rightarrow x=60:15\)
\(\Rightarrow x=4\)
Vậy x = 4
_Chúc bạn học tốt_
PD
2
20 tháng 9 2021
\(1734:17=102x17:17=102x1=102\)
\(\left(x-7\right)\)\(2-26=13x17-13x7=13\left(17-7\right)=13x10=130\)
\(\left(x-7\right)2=130+26=156\)
\(x-7=156:2=78\)
\(x=78+7=85\)
\(=>x=85\)
\(195-\left(15x+27\right)=4212:39=108\)
\(15x+27=195-108=87\)
\(15x=87-27=60\)
\(x=60:15=4\)
\(=>x=4\)
20 tháng 9 2021
- Tính nhẩm
1734 : 17 = 102
- Tìm x
(x - 7) .2 - 26 = 13.17 - 13.7
(x - 7) .2 - 26 = 13.(17 - 7)
(x - 7) .2 - 26 = 13. 10
(x - 7) .2 - 26 = 130
(x - 7) .2 = 130 + 26
(x - 7) .2 = 156
(x - 7) = 156 : 2
(x - 7) = 78
x = 78 + 7
x = 85
___________________
195 - (15x + 27) .39 = 4212 (dấu "[" đặt ở đấu tiên nên không cần thiết)
(15x + 27) .39 = 195 - 4212
(15x + 27) .39 = -4017
(15x + 27) = -4017 : 39
(15x + 27) = -103
15x = -103 -27
15x = -130
x = -130 : 15
x = -26/3
KN
15 tháng 7 2023
\(95-\left(3x-27\right).39=4212\)
\(95-\left(3x-27\right)=108\)
\(3x-27=-13\)
\(3x=14\)
\(x=\dfrac{14}{3}\)
15 tháng 7 2023
95−(3x−27).39=4212
95−(3x−27)=108
3x−27=−13
3x=14
từ đó suy ra x=14/3
GL
2
TT
8 tháng 2 2021
\(\dfrac{x+3}{97}+\dfrac{x+5}{95}+\dfrac{x+9}{91}=\dfrac{x+91}{9}+\dfrac{x+92}{8}+\dfrac{x+61}{39}\)
=> \(\dfrac{x+3}{97}+1+\dfrac{x+5}{95}+1+\dfrac{x+9}{91}+1=\dfrac{x+91}{9}+1+\dfrac{x+92}{8}+1+\dfrac{x+61}{39}+1\)
=> \(\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}=\dfrac{x+100}{9}+\dfrac{x+100}{8}+\dfrac{x+100}{39}\)
=> \(\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}-\dfrac{x+100}{9}-\dfrac{x+100}{8}-\dfrac{x+100}{39}=0\)
=> \(\left(x+100\right).\left(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\right)=0\)
=> x = - 100 (do \(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\ne0\)
8 tháng 2 2021
Ta có: \(\dfrac{x+3}{97}+\dfrac{x+5}{95}+\dfrac{x+9}{91}=\dfrac{x+91}{9}+\dfrac{x+92}{8}+\dfrac{x+61}{39}\)
\(\Leftrightarrow\dfrac{x+3}{97}+1+\dfrac{x+5}{95}+1+\dfrac{x+9}{91}+1=\dfrac{x+91}{9}+1+\dfrac{x+92}{8}+1+\dfrac{x+61}{39}+1\)
\(\Leftrightarrow\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}=\dfrac{x+100}{9}+\dfrac{x+100}{8}+\dfrac{x+100}{39}\)
\(\Leftrightarrow\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}-\dfrac{x+100}{9}-\dfrac{x+100}{8}-\dfrac{x+100}{39}=0\)
\(\Leftrightarrow\left(x+100\right)\left(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\right)=0\)
mà \(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\ne0\)
nên x+100=0
hay x=-100
Vậy: S={-100}
\(a,91-5.\left(5+x\right)=61\\ \Rightarrow=5.\left(5+x\right)=30\\ \Rightarrow5+x=6\\ \Rightarrow x=1.\\ b,\left[195-\left(3x-27\right)\right].39=4212\\ \Rightarrow195-\left(3x-27\right)=108\\ \Rightarrow3x-27=87\\ \Rightarrow3x=114\\ \Rightarrow x=38.\)
\(91-5.\left(5+x\right)=61\)
\(\Rightarrow5.\left(5+x\right)=91-61\)
\(\Rightarrow5.\left(5+x\right)=30\)
\(\Rightarrow5+x=\dfrac{30}{5}=6\)
\(\Rightarrow x=6-5=1\)
\(\left[195-\left(3x-27\right)\right].39=4212\)
\(\Rightarrow195-3x+27=\dfrac{4212}{39}=108\)
\(\Rightarrow222-3x=108\)
\(\Rightarrow3x=222-108=114\)
\(\Rightarrow x=\dfrac{114}{3}=38\)