294 - (7x-217)=3 mũ 8 nhân 3 mũ 17 chia 3 mũ 16 nhân 6 mũ 2
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a) \(\frac{75^3.3^7}{81^4.5^6}=\frac{5^3.3^3.5^3.3^7}{\left(3^4\right)^4.5^6}=\frac{5^6.3^3.3^7}{3^{16}.5^6}=\frac{3^{10}}{3^{16}}=\frac{1}{3^6}=\frac{1}{729}\)
b) \(\frac{6^6.4^2}{3^{12}.2^8}=\frac{2^6.3^6.\left(2^2\right)^2}{3^{12}.2^8}=\frac{2^6.3^6.2^4}{3^{12}.2^8}=\frac{2^{10}.3^6}{3^{12}.2^8}=\frac{2^2.1}{3^6}=\frac{4}{729}\)
c) \(\frac{34^5.2^5}{2^{14}.17^5}=\frac{2^5.17^5.2^5}{2^{14}.17^5}=\frac{2^{10}}{2^{14}}=\frac{1}{2^4}=\frac{1}{16}\)
a) \(\frac{7^3.5^8}{49.25^4}=\frac{7^3.5^8}{7^2.\left(5^2\right)^4}=7.\frac{5^8}{5^8}=7\)
b) \(\frac{3^9.25.5^3}{15.625.3^8}=\frac{3.3^8.5^2.5^3}{3.5.5^4.3^8}=\frac{5^5}{5^5}=1\)
c) Đề hơi sai roi bạn oi
d) \(\left(\frac{2}{5}-\frac{1}{2}\right)^2+\left(\frac{1}{2}+\frac{3}{5}\right)^2=\left(\frac{-1}{10}\right)^2+\left(\frac{11}{10}\right)^2=\frac{1}{100}+\frac{121}{100}=\frac{61}{50}\)
2.4^x - 1 = 128
=> 4^x - 1 = 64
=> x - 1 = 3
=> x = 4
b, 17.4^2 + 83.16
= 17.16 + 83.16
= 16(17 + 83)
= 16.100
= 1600
c, a^5 . 10^10.a^15
= a^20.10^10
d, 3{65 - [5(4 + 2.3) - 15] : 7}
= 3{65 - [5(4 + 6) - 15] : 7}
= 3{65 - [5.10 - 15] : 7}
= 3{65 - [50 - 15] : 7}
= 3{65 - 35 : 7}
= 3{65 - 5}
= 3.60
= 180
1: Ta có: \(\left(7x-3^2\right):5=8\)
\(\Leftrightarrow7x-9=40\)
hay x=7
a) \(2^3\cdot4^5=2^3\cdot2^{10}=2^{13}\)
b) \(3^4\cdot27^2=3^4\cdot3^6=3^{10}\)
c) \(16^{10}:8^2=2^{40}:2^6=2^{34}\)
d) \(12^3:3^3=\left(12:3\right)^3=4^3\)
e) \(3^4\cdot2^4=\left(3\cdot2\right)^4=6^4\)
g) \(9^{13}\cdot5^{26}=9^{13}\cdot25^{13}=\left(9\cdot25\right)^{13}=225^{13}\)
=))
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