Viết gọn các tích hoặc thương sau dưới dạng một lũy thừa rồi tính
p) (\(\frac{1}{8}\))4 : (-\(\frac{1}{4}\))5
Thanks nhiều ạ <3
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l) 27^8=(33)8=324
=>278:322=324:322
=324-22=32
m) 8^4=(23)4=212
45=(22)5=210
=>84:45=212:210
=212-10=22
a) \(27^8:3^{22}\)
\(=\left(3^3\right)^8:3^{22}\)
\(=3^{24}:3^{22}=3^{24-22}\)
\(=3^2\)
b) \(8^4:4^5\)
\(=\left(2^3\right)^4:\left(2^2\right)^5\)
\(=2^{12}:2^{10}=2^{12-10}=2^2\)
a) \(\left(\frac{27}{64}\right)^8:\left(\frac{3}{4}\right)^{22}=\left[\left(\frac{3}{4}\right)^3\right]^8:\left(\frac{3}{4}\right)^{22}=\left(\frac{3}{4}\right)^{24}:\left(\frac{3}{4}\right)^{22}=\left(\frac{3}{4}\right)^2\)
b) \(\left(\frac{2}{3}\right)^2.\left(-\frac{8}{27}\right).\left(-\frac{2}{3}\right)=\left(\frac{2}{3}\right)^2.\left(-\frac{2}{3}\right)^3.\left(-\frac{2}{3}\right)=\left(\frac{2}{3}\right)^2.\left(-\frac{2}{3}\right)^4=\left(\frac{2}{3}\right)^6\)
Ta có:
\(\begin{array}{l}{\left( {\frac{1}{4}} \right)^8} = {[{\left( {\frac{1}{2}} \right)^2}]^8} = {(\frac{1}{2})^{2.8}} = {(\frac{1}{2})^{16}};\\{\left( {\frac{1}{8}} \right)^3} = {[{(\frac{1}{2})^3}]^3} = {(\frac{1}{2})^{3.3}} = {(\frac{1}{2})^9}\end{array}\)
a: \(3\cdot3\cdot3\cdot3\cdot3=3^5\)
b: \(y\cdot y\cdot y\cdot y=y^4\)
c: \(5\cdot p\cdot5\cdot p\cdot2\cdot q\cdot4\cdot q=25\cdot2\cdot4\cdot p^2q^2=2\cdot\left(10qp\right)^2\)
d: \(a\cdot a+b\cdot b+c\cdot c+d\cdot d\cdot d\cdot d=a^2+b^2+c^2+d^4\)
\(5.p.p.5.p^2.q.4.q=\left(5.5.4\right).\left(p.p.p^2\right).\left(q.q\right)=100p^4.q^2\)
\(\left(\frac{1}{8}\right)^4:\left(-\frac{1}{4}\right)^5\)
\(=\frac{1}{8^4}:\frac{-1}{4^5}\)
\(=\frac{1}{2^{12}}:\frac{-1}{2^{10}}\)
\(=\frac{1}{2^{12}}.\frac{2^{10}}{-1}=\frac{1}{-4}\)