(5x-24).73=2.7 dấu chấm là dấu nhân
ai nhanh tk
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\(73\left(5x-24\right)=2.7\)
\(\Leftrightarrow5x-24=14:73=0.19178\)
\(\Leftrightarrow5x=0.19178+24=24.19178\)
\(\Leftrightarrow x=24.19178:5=4.838356\)
Vậy x=4.838356
32 . 41+ 46.73 + 32.59 +73.54
=32.(41+59)+73.(46+54)
=32.100+73.100
=100.(32+73)
=100.105 = 10500
32*41+46*73+32*59+73*54
=(32*(41+59))+(73*(54+46))
=(32*100)+(73*100)
=3200+7300
=11500 k cho minh nha thuuuuuuuuuuu
- Giải:
a) 29 + ( 132 + 868 ) + ( 237 + 763 )
= 29 + ( 1000 + 1000 )
= 29 + 2000 = 2029
b) 652 + 327 + 148 + 15 + 73
= ( 652 + 148 ) + ( 327 + 73 ) + 15
= ( 800 + 400 ) + 15 = 1215
-------Phần còn lại nhờ mấy bn khác lm hộ nhé-------
a) 29 + 132 + 237 + 868 + 763
= 29 + (132 + 868) + (237 + 763)
= 29 + 1000 + 1000
= 2029
b) 652 + 327 + 148 + 15 + 73
= (652 + 148) + (327 + 73) + 15
= 800 + 400 + 15
= 1215
c) 35 . 24 + 35 . 38 + 65 . 75 + 45 . 65
= 35(24 + 38) + 65(75 + 45)
= 35 . 62 + 65 . 120
= 5 . 7 . 2 . 31 + 65 . 12 . 10
= 10 . 7 . 31 + 65 . 12 .10
= 10(7 . 31 + 65 . 12)
= 10(217 + 780)
= 10 . 997
= 9970
d) 3 . 25 + 4 . 37 . 6 + 2 . 38 . 12
= 3 . 25 + 4 . 37 . 2 . 3 + 2 . 38 . 12
= 3 . 25 + 12 . 37 . 2 + 2 . 38 . 12
= 3 . 25 + 12 . 2(37 + 38)
= 3 . 25 + 12 . 2 . 75
= 3 . 25 + 12 . 2 . 3 . 25
= 3 . 25(1 + 12 . 2)
= 3 . 25 . 25
= 1875
1/1.2+1/2.3+1/3.4+......+1/2003.2004=1/1-1/2+1/2-1/3+1/3-1/4+......+1/2003-1/2004
=1/1-1/2004
=2003/2004
1/1.2+1/2.3+1/3.4+.......1/2003.2004
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2003}-\frac{1}{2004}\)
\(=1-\frac{1}{2004}\)
\(=\frac{2003}{2004}\)
\(\frac{27.13-12}{24+37.12}\)
\(=\frac{351-12}{24+444}\)
\(=\frac{113}{156}\)
đặt S=1.2.3+2.3.4+....+47.48.49
4S=1.2.3.(4-0)+2.3.4.(5-1)+...+47.48.49.(50-46)
4S=1.2.3.4-1.2.3+2.3.4.5-1.2.3.4+....+47.48.49.50-46.47.48.49
4S=47.48.49.50-1.2.3
S=(47.48.49.50-1.2.3):4
\(\frac{1}{2\cdot x}-2021-\frac{1}{4}-\frac{1}{12}-\frac{1}{24}-...-\frac{1}{222}=\frac{6}{11}\)
\(\frac{1}{2\cdot x}-2021-\left(\frac{1}{4}+\frac{1}{12}+\frac{1}{24}+...+\frac{1}{222}\right)=\frac{6}{11}\)
....
Cái dãy \(\frac{1}{4}+\frac{1}{12}+\frac{1}{24}+...+\frac{1}{222}\) nó không có quy luật, không tính được
Sửa đề\(\frac{1}{2x-2021}-\frac{1}{4}-\frac{1}{12}-\frac{1}{24}-...-\frac{1}{220}=\frac{6}{11}\)
=> \(\frac{1}{2x-2021}-\left(\frac{1}{4}+\frac{1}{12}+\frac{1}{24}+...+\frac{1}{220}\right)=\frac{6}{11}\)
=> \(\frac{1}{2x-2021}-\frac{1}{2}\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\right)=\frac{6}{11}\)
=> \(\frac{1}{2x-2021}-\frac{1}{2}\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)=\frac{6}{11}\)
=> \(\frac{1}{2x-2021}-\frac{1}{2}\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+..+\frac{1}{10}-\frac{1}{11}\right)=\frac{6}{11}\)
=> \(\frac{1}{2x-2021}-\frac{1}{2}\left(1-\frac{1}{11}\right)=\frac{6}{11}\)
=> \(\frac{1}{2x-2021}-\frac{1}{2}.\frac{10}{11}=\frac{6}{11}\)
=> \(\frac{1}{2x-2021}-\frac{5}{11}=\frac{6}{11}\)
=> \(\frac{1}{2x-2021}=1\)
=> 2x - 2021 = 1
=> 2x = 2022
=> x = 1011
Vậy x = 1011
(5x-24).73=2.7
5x - 24 = 14 : 73
5x = 14/73 + 24
5x = 1766/73
x= 1766/72 . 1/5
x= 1766/365