2/3 x -1/2 =1/10
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Câu 1 :
a, \(\frac{3\left(2x+1\right)}{4}-\frac{5x+3}{6}=\frac{2x-1}{3}-\frac{3-x}{4}\)
\(\Leftrightarrow\frac{6x+3}{4}+\frac{3-x}{4}=\frac{2x-1}{3}+\frac{5x+3}{6}\)
\(\Leftrightarrow\frac{5x+6}{4}=\frac{9x+1}{6}\Leftrightarrow\frac{30x+36}{24}=\frac{36x+4}{24}\)
Khử mẫu : \(30x+36=36x+4\Leftrightarrow-6x=-32\Leftrightarrow x=\frac{32}{6}=\frac{16}{3}\)
tương tự
\(\frac{19}{4}-\frac{2\left(3x-5\right)}{5}=\frac{3-2x}{10}-\frac{3x-1}{4}\)
\(< =>\frac{19.5}{20}-\frac{8\left(3x-5\right)}{20}=\frac{2\left(3-2x\right)}{20}-\frac{5\left(3x-1\right)}{20}\)
\(< =>95-24x+40=6-4x-15x+5\)
\(< =>-24x+135=-19x+11\)
\(< =>5x=135-11=124\)
\(< =>x=\frac{124}{5}\)
a: =>14x+20+5=6x-9-9x
=>14x+25=-3x-9
=>17x=-34
=>x=-2
b: =>\(2x^2-30x+2x-30=2x^2+10x-10x-50\)
=>-28x-30=-50
=>-28x=-20
=>x=20/28=5/7
c: =>2x+x^3-x=x^3+1
=>x=1
d: =>x^3-3x^2+3x-1-x(x^2+2x+1)=10x-2x^2-11x-22
=>x^3-3x^2+3x-1-x^3-2x^2-x=-2x^2-x-22
=>-5x^2+2x-1+2x^2+x+22=0
=>-3x^2+3x+21=0
=>x^2-x-7=0
=>\(x=\dfrac{1\pm\sqrt{29}}{2}\)
Câu 1 : \(\frac{10}{3}\cdot x-\frac{1}{2}=\frac{1}{10}\)
\(\Rightarrow\frac{10}{3}\cdot x=\frac{3}{5}\Rightarrow x=\frac{9}{50}\)
Câu 2 : \(\frac{1}{3}\cdot x+\frac{1}{3}\cdot x=\frac{1}{8}\Rightarrow x\cdot\left(\frac{1}{3}+\frac{1}{3}\right)=\frac{1}{8}\)
\(x\cdot\frac{2}{3}=\frac{1}{8}\Rightarrow x=\frac{3}{16}\)
Câu 3 : \(\left[3x-1\right]\left[\frac{1}{2}x-\frac{2}{5}\right]=0\)
\(\Rightarrow3x-1=0\)hoặc \(\frac{1}{2}x-\frac{2}{5}=0\)
( vô lí ) x = 4/5
\(\frac{1}{2}.\frac{9}{10}+\frac{1}{2}.\frac{8}{10}+\frac{1}{2}.\frac{3}{10}=\frac{1}{2}.\left(\frac{9}{10}+\frac{8}{10}+\frac{3}{10}\right)=\frac{1}{2}.2=1\)
Dấu chấm là dấu nhân nhé
= \(\frac{1}{2}\times\left(\frac{9}{10}+\frac{8}{10}+\frac{3}{10}\right)=\frac{1}{2}\times\frac{20}{10}=\frac{1}{2}\times2=1\)
Bài 1:
a: x+1/2=5/6
nên x=5/6-1/2=1/3
b: x+1/4=3/4
nên x=3/4-1/4=2/4=1/2
c: x+3/10=1/2
nên x=1/2-3/10=5/10-3/10=1/5
d: x+1/4=3/8
nên x=3/8-1/4=3/8-2/8=1/8
\(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\\ \Rightarrow\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}\\ \Rightarrow\dfrac{2}{3}x=\dfrac{3}{5}\\ \Rightarrow x=\dfrac{3}{5}:\dfrac{2}{3}\\ \Rightarrow x=\dfrac{9}{10}\)
\(...\Rightarrow\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}\)
\(\Rightarrow\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{5}{10}\)
\(\Rightarrow\dfrac{2}{3}x=\dfrac{6}{10}=\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{3}{5}.\dfrac{3}{2}=\dfrac{9}{10}\)