b, \(\frac{-4}{3}x=\frac{5}{11}+\frac{4}{-9}\)
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B=\(6\frac{4}{9}-4\frac{4}{9}+3\frac{7}{11}\)
B=\(2+3\frac{7}{11}\)
B=\(5\frac{7}{11}\)
B = \(5\frac{7}{11}=\frac{62}{11}\)
C = 1
D = \(\frac{5}{2}=2\frac{1}{2}\)
\(A=\left(-\frac{5}{11}\right).\frac{7}{15}+\frac{11}{-5}.\frac{30}{33}\)
\(A=-\frac{7}{33}+-2\)
\(A=-\frac{73}{33}\)
[ A] = -2
\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)
\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)
\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)
\(\Rightarrow-1\le x< 6\)
\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)
Bài b tương tự
\(a.\frac{4}{5}\times\frac{3}{x}\times\frac{2}{11}=\frac{24}{165}\)
\(\frac{3}{x}=\frac{24}{165}:\frac{4}{5}:\frac{2}{11}\)
\(\frac{3}{x}=1\)
\(\Rightarrow x=3\)
\(b.\frac{4}{3}:\frac{x}{5}=\frac{5}{13}\times\frac{4}{9}\)
\(\frac{4}{3}\times\frac{5}{x}=\frac{20}{117}\)
\(\frac{5}{x}=\frac{20}{117}:\frac{4}{3}\)
\(\frac{5}{x}=\frac{5}{39}\)
\(\Rightarrow x=39\)
Đúng nha
\(\frac{-4}{3}x=\frac{5}{11}+\frac{4}{-9}\)
\(=\frac{-4}{3}x=\frac{-1}{99}\)
\(=x=\frac{-1}{99}:\frac{-4}{3}\)
\(=x=\frac{-1}{99}.\frac{3}{-4}\)
\(=x=\frac{1}{132}\)
chúc bạn học giỏi
x=\(\frac{-1}{132}\)