\(\dfrac{13}{50}+9\%+\dfrac{41}{100}+0,24\)
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\(\dfrac{13}{50}+9\%+\dfrac{41}{100}+0,24\)
\(=0,26+0,09+0,41+0,24\)
\(=\left(0,26+0,24\right)+\left(0,09+0,41\right)\)
\(=0,5+0,5\)
\(=1\)
\(\dfrac{13}{50}+9\%+\dfrac{41}{100}+0,24\)
\(=\dfrac{13}{50}+\dfrac{9}{100}+\dfrac{41}{100}+\dfrac{6}{25}\)
\(=\dfrac{13}{50}+\dfrac{9}{100}+\dfrac{41}{100}+\dfrac{12}{50}\)
\(=\left(\dfrac{13}{50}+\dfrac{12}{50}\right)+\left(\dfrac{9}{100}+\dfrac{41}{100}\right)\)
\(=\dfrac{25}{50}+\dfrac{50}{100}\)
\(=\dfrac{25}{50}+\dfrac{25}{50}\)
\(=\dfrac{50}{50}=1\)
\(\dfrac{13}{50}+9\%+\dfrac{41}{100}+0,24\)
\(=\dfrac{26}{100}+\dfrac{9}{100}+\dfrac{41}{100}+\dfrac{24}{100}\)
\(=\left(\dfrac{26}{100}+\dfrac{24}{100}\right)+\left(\dfrac{9}{100}+\dfrac{41}{100}\right)\)
\(=\dfrac{50}{100}+\dfrac{50}{100}=\dfrac{1}{2}+\dfrac{1}{2}=\dfrac{2}{2}=1\)
Bài 3
a,26/100+0,009+41/100+0,24
0,26+0,09+0,41+0,24
(0,26+0,24)+(0,09+0,41)
0,5+0,5
=1
b,9+1/4+6+2/7+7+3/5+8+2/3+2/5+1/3+5/7+3/4
(9+6+7+8)+(2/7+5/7)+(1/4+3/4)+(3/5+2/5)+(2/3+1/3)
30+1+1+1+1
=34
Bài 4,5 khó quá mik ko bít lamf^^))
Bài 4: a, \(\dfrac{2008}{2009}\) < 1; \(\dfrac{10}{9}\) > 1
\(\dfrac{2008}{2009}\) < \(\dfrac{10}{9}\)
b, \(\dfrac{1}{a+1}\) và \(\dfrac{1}{a-1}\)
Ta có: a + 1 > a - 1 ⇒ \(\dfrac{1}{a+1}\) < \(\dfrac{1}{a-1}\)
\(15-\dfrac{x}{2}=\dfrac{3}{7}\)
\(\dfrac{x}{2}=15-\dfrac{3}{7}=\dfrac{15\cdot7-3}{7}=\dfrac{102}{7}\)
\(x=\dfrac{102}{7}\cdot2=\dfrac{204}{7}\)
Áp dụng tính chất dãy tỉ số bằng nhau:\(\dfrac{\left(5z-3y\right)+\left(3x-2z\right)+\left(2y-5x\right)}{2+5+3}\)
=\(\dfrac{\left(3x-5x\right)+\left(-3y+2y\right)+\left(5z-2z\right)}{2+5+3}\)
=\(\dfrac{-2x-y+3z}{2+5+3}\)(???!!!!)
=\(\dfrac{-2x}{2}=\dfrac{-y}{5}=\dfrac{3z}{3}\)
=\(\dfrac{2}{-2x}=\dfrac{5}{-y}=\dfrac{3}{3z}\)
tớ xin chịu trận vì ko chứng minh được :(((
nó lại ra như thế này
125/90=25/18
84/91=12/13
75/45=25/15=5/3
6/7=18/21=54/63=104/126
A = \(\dfrac{13}{50}\) + 9% + 41/100 + 0,24
A = 0,26 + 0,09 + 0,41 + 0,24
A = (0,26 + 0,24) + ( 0,09 + 0,41)
A = 0,5 + 0,5
A = 1
\(\dfrac{13}{50}+9\%+\dfrac{41}{100}+0,24\)
\(=\dfrac{26}{100}+\dfrac{9}{100}+\dfrac{41}{100}+\dfrac{24}{100}\)
\(=\left(\dfrac{26}{100}+\dfrac{24}{100}\right)+\left(\dfrac{9}{100}+\dfrac{41}{100}\right)\)
\(=\dfrac{1}{2}+\dfrac{1}{2}\)
\(=1\)
Thank Nhé