Bài 1: Tính bằng 2 cách
a) (2/3 x 4/5) x 5/6
b) (1/2 + 1/3) x 1/5
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a,C1
(5/6 + 5/8) x 2/3
= 35/24 x 2/3
=35/36
C2
(5/6 + 5/8) x 2/3
= 5/6x2/3 + 5/8x2/3
= 10/18 + 10/24
= 35/36
b,C1
7/5 x 3/4 - 1/2 x 3/4
= 21/20 - 3/8
= 27/40
C2
7/5 x 3/4 - 1/2 x 3/4
=3/4 x (7/5-1/2)
=3/4x9/10
=27/40
a, 5/6 x (1/8x2/3)
=5/6 x 1/12
=5/72
b,(7/5 - 1/2) x 3/4
=0,9 x 3/4
=3,06
c,(5/6+5/8) x 2/3
=70/48 x 2/3
=35/36
a, 5/6 x (1/8x2/3)
=5/6 x 1/12
=5/72
b,(7/5 - 1/2) x 3/4
=0,9 x 3/4
=3,06
c,(5/6+5/8) x 2/3
=70/48 x 2/3
=35/36
a) C1
\(\dfrac{1}{8}\times\dfrac{5}{6}+\dfrac{5}{6}\times\dfrac{2}{3}=\dfrac{5}{6}\times\left(\dfrac{1}{8}+\dfrac{2}{3}\right)=\dfrac{5}{6}\times\dfrac{19}{24}=\dfrac{95}{144}\)
C2
\(\dfrac{1}{8}\times\dfrac{5}{6}+\dfrac{5}{6}\times\dfrac{2}{3}=\dfrac{5}{48}+\dfrac{10}{18}=\dfrac{95}{144}\)
b) C1
\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{3}{4}\times\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{3}{4}\times\dfrac{9}{10}=\dfrac{27}{40}\)
C2
\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{21}{20}-\dfrac{3}{8}=\dfrac{27}{40}\)
c) C1
\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\dfrac{35}{24}\times\dfrac{2}{3}=\dfrac{35}{36}\)
C2
\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\left(\dfrac{5}{6}\times\dfrac{2}{3}\right)+\left(\dfrac{5}{8}\times\dfrac{2}{3}\right)=\dfrac{5}{9}+\dfrac{5}{12}=\dfrac{35}{36}\)
a: =5/48+10/18=95/144
b: =3/4(7/5-1/2)=3/4x9/10=27/40
c: =2/3x35/24=70/72=35/36
a: =5/6(1/8+2/3)=5/6*19/24=95/144
b: =3/4(7/5-1/2)=27/40
c: =35/24*2/3=35/36
Cách 1: a. (125.63):5=7875:5
=1575
Cách 2: a. (125.63):5=(125:5).63
=25.63
=1575
(Bạn sửa dấu " . " thành dấu nhân giúp mik nhé)
Cách 1: a. (125.63):5=7875:5
=1575
Cách 2: a. (125.63):5=(125:5).63
=25.63
=1575
(Bạn sửa dấu " . " thành dấu nhân giúp mik nhé)
a: =6-6=0
b: \(=\dfrac{-5}{4}:\dfrac{2-7}{8}+\dfrac{3}{2}\cdot\dfrac{2-5}{6}\)
\(=\dfrac{-5}{4}\cdot\dfrac{8}{-5}+\dfrac{3}{2}\cdot\dfrac{-3}{6}\)
\(=2+\dfrac{-9}{12}=2-\dfrac{3}{4}=\dfrac{5}{4}\)
c: \(=2,5\cdot\left(-0,65\right)+1,5\left(-0,3-0,35\right)=-0,65\cdot4=-2,6\)
`( 2/3 xx 4/5) xx 5/6`
`= 8/15 xx 5/6`
`= 40/90`
`=4/9`
__
`( 2/3 xx 4/5) xx 5/6`
`= 2/3 xx (4/5 xx 5/6)`
`= 2/3 xx 2/3`
`= 4/9`
-------
`(1/2 + 1/3) xx 1/5`
`= ( 3/6 +2/6) xx 1/5`
`= 5/6 xx1/5`
`= 5/30`
`=1/6`
__
`(1/2 + 1/3) xx 1/5`
`=1/2 xx 1/5 + 1/3 xx 1/5`
`= 1/10 + 1/15`
`=1/6`
a)
c1
`(2/3xx4/5)xx5/6`
`=8/15xx5/6`
`=4/9`
c2
`(2/3xx4/5)xx5/6`
`=2/3xx4/5xx5/6`
`=2/3xx5/6xx4/5`
`=5/9xx4/5`
`=4/9`
b)
c1
`(1/2+1/3)xx1/5`
`=(3/6+2/6)xx1/5`
`=5/6xx1/5`
`=1/6`
c2
`(1/2+1/3)xx1/5`
`=1/2xx1/5+1/3xx1/5`
`=1/10+1/15`
`=3/30+2/30`
`=5/30=1/6`