CM:
2121/4747=21212121/47474747
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a . 24/50 < 51/100 b . 2003/2013 < 2004/2014 c . 2121/3131 = 21212121/31313131
= 18 x \(\left(\frac{19.1010101}{21.1010101}+\frac{8.11111}{9.11111}\right)\)= 18 x ( \(\frac{19}{21}+\frac{8}{9}\)) = 9 x 2 ( \(\frac{57+56}{63}\))
= 9 x 2 x \(\frac{113}{63}\)=\(\frac{226}{7}\)
\(\left(\frac{5}{7}:\frac{3}{4}\right)\cdot\frac{2}{5}+\frac{13131313}{21212121}\)
\(=\frac{20}{21}\cdot\frac{2}{5}+\frac{13131313}{21212121}\)
\(=\frac{8}{21}+\frac{13131313}{21212121}\)
\(=1\)
^_^^_^^_^
\(=18x\frac{19x1010101}{21x1010101}+\frac{8x11111}{9x11111}=18x\frac{19}{21}+\frac{8}{9}\)
=>(\(\frac{7}{4}+\frac{21}{20}+\frac{7}{10}+\frac{1}{2}\))-x=-2015
=>(1,75+1,05+0,7+0,5)-x=-2015
=>4-x=-2015
=>x=4-(-2015)
=>x=2019
(\(\frac{2121}{1212}+\frac{2121}{2020}+\frac{2121}{3030}+\frac{2121}{4242}\)) - x = -2015
=> ( \(\frac{21}{12}+\frac{21}{20}+\frac{21}{30}+\frac{21}{42}\) ) - x = -2015
=> ( \(\frac{7}{4}+\frac{21}{20}+\frac{21}{30}+\frac{1}{2}\) ) - x = -2015
=> ( 1,75 + 1,05 + 0,7 + 0,5 ) - x = -2015
=> 4 - x = -2015
=> x = 4 - ( -2015 )
=> x = 4 + 2015
=> x = 2019