7/25 + 4/38 + 18/25 - 2 và 2/9
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GL
24 tháng 8 2023
a) \(\dfrac{2}{9}+\dfrac{5}{9}=\dfrac{7}{9};\dfrac{5}{9}+\dfrac{2}{9}=\dfrac{7}{9}\)
Vậy: \(\dfrac{2}{9}+\dfrac{5}{9}=\dfrac{5}{9}+\dfrac{2}{9}\)
b) \(\dfrac{3}{25}+\dfrac{4}{25}+\dfrac{7}{25}=\dfrac{14}{25};\dfrac{3}{25}+\dfrac{7}{25}+\dfrac{4}{25}=\dfrac{14}{25}\)
Vậy: \(\dfrac{3}{25}+\dfrac{4}{25}+\dfrac{7}{25}=\dfrac{3}{25}+\dfrac{7}{25}+\dfrac{4}{25}\)
9 tháng 8 2017
a) \(\dfrac{7}{-25}+\dfrac{8}{25}=\dfrac{-7}{25}+\dfrac{8}{25}=\dfrac{1}{25}\)
\(\dfrac{4}{5}+\dfrac{4}{-18}=\dfrac{4}{5+\left(-18\right)}=\dfrac{4}{-13}=\dfrac{-4}{13}\)
\(\dfrac{7}{21}+\dfrac{9}{-36}=\dfrac{1}{3}+\dfrac{1}{-4}=\dfrac{1}{3+\left(-4\right)}=\dfrac{1}{-1}=1\)
b) \(\dfrac{12}{20}-\dfrac{2}{5}=\dfrac{12}{20}+\left(\dfrac{-2}{5}\right)=\dfrac{3}{5}+\dfrac{-2}{5}=\dfrac{3+\left(-2\right)}{5}=\dfrac{1}{5}\)
\(\dfrac{2}{3}-\dfrac{-5}{6}=\dfrac{2}{3}+\dfrac{5}{6}=\dfrac{4}{6}+\dfrac{5}{6}=\dfrac{9}{6}=\dfrac{3}{2}\)
\(6-\dfrac{3}{20}=6+\dfrac{-3}{20}=\dfrac{60}{60}+\dfrac{-9}{60}=\dfrac{51}{60}\)
c) \(\dfrac{2}{21}.\dfrac{-7}{3}=\dfrac{2.\left(-1\right)}{7.3}=\dfrac{-2}{21}\)
\(\dfrac{27}{28}.\left(-21\right)=\dfrac{27.\left(-21\right)}{28}=\dfrac{-567}{28}\)
\(\dfrac{-15}{7}.\dfrac{-14}{25}=\dfrac{-3.\left(-2\right)}{1.5}=\dfrac{6}{5}\)
NH
1
28 tháng 3 2022
a: \(=\dfrac{15}{2}-\dfrac{14}{5}=\dfrac{75-28}{10}=\dfrac{47}{10}\)
b: \(=\dfrac{39}{6}-\dfrac{9}{4}=\dfrac{78-27}{12}=\dfrac{45}{12}=\dfrac{15}{4}\)
c: \(=\dfrac{38}{5}-\dfrac{19}{4}=\dfrac{57}{20}\)
d: \(=1\cdot\dfrac{95}{9}=\dfrac{95}{9}\)
e: \(=\dfrac{3}{5}\cdot\dfrac{25}{9}=\dfrac{5}{3}\)
31 tháng 1 2022
1: \(=\left(217-213+186\right)+\left(-14-49+54\right)\)
\(=190-9=181\)
2: \(=-38\cdot25+38\cdot4-25\cdot4+25\cdot38\)
\(=13\cdot4=52\)
3: \(=-39\cdot5+39\cdot99+99\cdot10-99\cdot39\)
\(=-195+990=795\)
4: =(1+3-5-7)+(9+11-13-15)+...+(393+395-397-399)
=(-8)+(-8)+...+(-8)
=-800
DT
0
đề bài yêu cầu j v em