2 và 1 phần 5 x + x = 22 phần 15 . Tím x ?
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Ta có:
\(\frac{5}{7}+\frac{2}{3}.x=\frac{3}{11}\)
\(\Rightarrow\frac{2}{3}.x=\frac{3}{11}-\frac{5}{7}\)
\(\Rightarrow\frac{2}{3}.x=-\frac{34}{77}\)
\(\Rightarrow x=-\frac{34}{77}:\frac{2}{3}\)
\(\Rightarrow x=-\frac{34}{77}.\frac{3}{2}\)
\(\Rightarrow x=-\frac{13}{11}\)
Ta có:
\(-\frac{22}{15}.x+\frac{1}{3}=\left|-\frac{2}{3}+\frac{1}{5}\right|\)
\(\Rightarrow-\frac{22}{15}.x+\frac{1}{3}=\left|-\frac{7}{15}\right|\)
\(\Rightarrow-\frac{22}{15}.x+\frac{1}{3}=\frac{7}{15}\)
\(\Rightarrow-\frac{22}{15}.x=\frac{7}{15}-\frac{1}{3}\)
\(\Rightarrow-\frac{22}{15}.x=\frac{2}{15}\)
\(\Rightarrow x=\frac{2}{15}:-\frac{22}{15}\)
\(\Rightarrow x=\frac{2}{15}.-\frac{15}{22}\)
\(\Rightarrow x=-\frac{1}{11}\)
a: -3/4x12=-36/4=-9
b: \(=\dfrac{7}{15}\cdot\dfrac{10}{21}=\dfrac{7}{21}\cdot\dfrac{10}{15}=\dfrac{1}{3}\cdot\dfrac{2}{3}=\dfrac{2}{9}\)
c: \(=\dfrac{7}{18}\cdot\dfrac{12}{21}=\dfrac{12}{18}\cdot\dfrac{7}{21}=\dfrac{2}{3}\cdot\dfrac{1}{3}=\dfrac{2}{9}\)
d: \(=\dfrac{11}{15}\cdot\dfrac{5}{22}=\dfrac{11}{22}\cdot\dfrac{5}{15}=\dfrac{1}{2}\cdot\dfrac{1}{3}=\dfrac{1}{6}\)
e: \(=-\dfrac{8}{15}\cdot\dfrac{5}{4}=\dfrac{-40}{60}=\dfrac{-2}{3}\)
f: \(=-15\cdot\dfrac{3}{5}=-9\)
\(a.32,5-3\cdot0,87=32,5-2,61=29,89\)
\(8,5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8,5\cdot\left(\dfrac{3}{2}+\dfrac{4}{4}\right):5\\ =8,5\cdot\left(\dfrac{6}{4}+\dfrac{4}{4}\right):5\\ =8,5\cdot\dfrac{10}{4}:5\\ =\dfrac{85}{4}:5\\ =\dfrac{17}{4}\)
\(b.30,96-6,45+14,4:3=30,96-6,45+4,8\\ =29,31\)
\(\dfrac{2}{5}\cdot\left(\dfrac{4}{5}-\dfrac{1}{2}\right)=\dfrac{2}{5}\cdot\left(\dfrac{8}{10}-\dfrac{5}{10}\right)\\ =\dfrac{2}{5}\cdot\dfrac{3}{10}=\dfrac{3}{25}\)
bài 2
\(a.2,5\cdot12,5\cdot8\cdot0,4=\left(2,5\cdot0,4\right)\left(12,5\cdot8\right)\\ =1\cdot100=100\)
b,\(\dfrac{12}{15}\cdot\dfrac{5}{6}\cdot\dfrac{3}{20}\cdot\dfrac{32}{5}=\dfrac{12\cdot5\cdot3\cdot32}{15\cdot6\cdot20\cdot5}\\ =\dfrac{3\cdot4\cdot5\cdot3\cdot4\cdot8}{3\cdot5\cdot2\cdot3\cdot5\cdot4\cdot5}=\dfrac{16}{25}\)
Bài 1:
a) \(32.5-3\cdot0.87=32.5-2.61=29.89\)
\(8.5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8.5\cdot\dfrac{5}{2}:5=\dfrac{17}{2}\cdot\dfrac{5}{2}:5=\dfrac{85}{4}\cdot\dfrac{1}{5}=\dfrac{17}{4}\)
a)x-5/7=-2/3+1/3
x-5/7=-1/3
x=-1/3+5/7
x=8/21
b)1/3x+5/7=-9/4
x+5/7=-9/4:1/3
x+5/7=-27/4
x=-27/4-5/7
x=-209/28
a: x-5/7=-2/3+1/3
=>x-5/7=-1/3
=>x=-1/3+5/7=8/21
b: 1/3*x+5/7=-9/4
=>x*1/3=-9/4-5/7=-83/28
=>x=-83/28:1/3=-83/28*3=-249/28
c: 1/6x:1/4=-1/24
=>1/6x=-1/96
=>x=-1/16
a)13,2 - x = -4,3
=> x = 13,2 - ( -4,3)
=> x = 17,5
b)x phần 3 = 20 phần 15
\(\dfrac{x}{3}=\dfrac{20}{15}=>20.3=x.15=>60=x.15=>x=60:15=>x=4\)
c) 2 phần 3 - 1 phần 3 x = -5 phần 3 + 1 phần 2
Mong bạn viết lại đề giúp mình
d) x - 3 phần 5 = -7 phần 10
\(\dfrac{x-3}{5}=\dfrac{-7}{10}=>5.-7=\left(x-3\right).10=>-35=\left(x-3\right).10=>x-3=-35:10=>x-3=\text{-3,5}=>x=\text{-3,5}+3=>x=6,5\)
Bài 1 :Bỏ dấu ngoặc
2007-(7-3+4)
= 2007 -7+3-4
= 1999
6+[(-5) + 4 - 1 ]
= 6-5+4-1
=4
5-[(-6+8-2]
= 5+6-8+2
=5
-10+(7-3+1)
= -10 +7-3+1
= -5
Bài 3 Tìm x
\(\dfrac{1}{3} = \dfrac{x}{6}\)
\(<=> x= \dfrac{1.6}{3}\)
\(<=> x=2\)
2:
a: =>x-1/5=2/15
=>x=2/15+3/15=5/15=1/3
b: =>x+7/12=-5/6-2/6=-7/6
=>x=-14/12-7/12=-21/12=-7/4
c: =>x+2/3=-10/3
=>x=-4
d: =>1/4:x=-11/4
=>x=-1/4:11/4=-1/11
e: =>8:x=1,6
=>x=5
a 25 phần 41
b 9
c 1 phần 12
d 12
e 14 phần 15
f 24 phần 7
Ta có: 2/1/5x+x=22/15
11/5x+x=22/15
16/5x=22/15
x=22/15:16/15
x=11/8
Vậy x=11/8
11/8 nha ban